Variable Variables, a problem.

[theeclypse]

Hi, I know that with variable variables, you can do the following:-

$foo = "bar";
echo $$foo;

and the output will be bar.

but, in my script, the value of "bar", will be given dynamically, i.e. it will be given, by the return string of a function. e.g.

$foo = getSomeString($bla);

but if i then do

echo $$foo;

i get no output, is there something im doing wrong?

[Anon]

are you sure, that:
$foo = "bar";
echo $$foo;

will print bar and not the value of $bar ?

ali

[evgeny]

$bar="test";
$foo = "bar";
echo $$foo;

The output will be test

So in order to get output in your case
result of getSomeString($bla) should be declared variable