Extract filename from url?

Anon

Hello,

How can extract the filename of a url?

I tryed the following code:
<?
$url="http://localhost.com/test.txt";
ereg("/(.+)$", $url, $ext);
print $ext[0];
?>

but that results in "//localhost.com/test.txt".

How can i "say" to the regex that he should get the last found "/", so that the result is: "test.txt"

Thanks, Twan

sp0rk

Use basename(), like this;

$url = "http://localhost.com/test.txt";
print basename($url);

Anon

Thanks it works like charm!

I'm now trying to extract the filename without the extension:

$url="http://localhost.com/test.txt";
$url=basename($url);
ereg(".(.+)", $url, $ext);
$name=basename($url,$ext[0]);

but php bugs me with a warning: "Warning: Wrong parameter count for basename() in /usr/local/apache/htdocs/ding/test.php on line 5"

The php documentation says "basename" can have 2 parameters, why is php complaining?

sp0rk

Works here. Can't see any reason why it shouldn't work for you, as long as you're running PHP 4.1.0 or greater, which is the version of PHP where the second parameter was added to basename.