displaying photo in a table format

[Anon]

I am using the following script to display a list of thumb size photos. It works fine as a list, but now I want to convert it over into a table format. Could anyone show me a script I could use to convert the following data, so it would print the results for each photo in a separate table cell. I will be using 3 columns and 5 rows per page in my display.
Thanks

echo "<A HREF='pg2.php?id=" . $result["id"] . "'>" ;
echo "$title<br>";
echo "$time";
echo " $city";
echo " $state<br>";
echo ("<img src=\"$photo\" border=0><P><HR width=400 align=left></A>");

[bastien]

echo "<table>";

//data loop to feed in all data

echo "<tr><td><A HREF='pg2.php?id=" . $result["id"] . "'></td>" ;
echo "<td>$title</td>";
echo "<td>$time</td>";
echo " <td>$city</td>";
echo " <td>$state</td>";
echo ("<td><img src=\"$photo\" border=0><P><HR width=400 align=left></A></td></tr>");

//end of data loop

echo "<table>";

hth
bastien

[Anon]

Hi,
Thanks for the code. I was able to use it to display my photo's in a table cell, but I must have confused you on the format I was looking for.
Instead of having one piece of information in each column, I want to display one photo, and the information for that photo in each column. That way I can show 5 photo's side by side.

[Anon]

$cols = 3; //Columns per row

for ($i=1; $i<$numImg; $i++) {
$rem = $i % $cols;
//Start new row
if (($i == 1) || (($i > $cols) && ($rem == 1))) {
echo '<tr>';
}
echo '<td>YOUR IMAGE STUFF...</td>';

//End row
if (($i == $numImg) || (($i >= $cols) && ($rem == 0))) {
echo '</tr>';
}
}

//Might need to tweak the IF condition clauses a bit, but it should work... 🙂

[Anon]

That was just what I needed. Thanks for your help.
FTW