variables not passing on

[msi3753]

okay peeps, its 4am and i'm really tired, but besides that, i can't figure out for the life of me why this code isn't working. First I have an include file... here is the top code + one if statement

$tall = array ("256","224");
$wide = array ("224","256");
$tallbottom = "<img src=\"images/mame/bottom.gif\" width=\"407\" height=\"195\" />";
$widebottom = "<img src=\"images/mame/bottomwide.gif\" width=\"435\" height=\"195\" />";

if ($QUERY_STRING == '1943'){
$game = "1943";
$tall[1] = $height;
$tall[2] = $width;
$tallbottom = $bottom;
}

Now when I go to the page, and try to echo all four variables in the if statement, only the $game variable echos, the rest are nill. Any ideas?

-Thx,
Tony

[Anon]

Try:

if ($QUERY_STRING == '1943'){
$game = "1943";
$height = $tall[1];
$width = $tall[2];
$bottom = $tallbottom;
}

[msi3753]

AHH, so simple, yes that worked great, thank you very much =). This is another example of why not to code at 4am with no caffeine. 😉

[msi3753]

Edit: I spoke too soon. $width still isn't being echo'ed, but I think I am on the right track now =).

[msi3753]

Defining the variables first and starting the array at 0 then 1 (instead of 1 and 2) worked gr8. Thanks again for all the help, and maybe this will help a fellow php programming insomniac.

[lennie]

Yup, had similar problem but after reading all the suggestions my problem is fixed. Thanks Guys.