LOST - CLI and argv/ argc problems

louash

using somthing like this:

#!/usr/bin/php -q
<?php
    var_dump($argv);
?>

in a file called "test", and then doing:

./test 1 2 3 4

results in an output of:

NULL

I need help. I've got 3 Mb of code written that suddenly needs to call other scripts and I can't seem to pass variables.

Tried this on Freebsd 4.5/ Solaris (5-something, I forget to be honest) and get the same results using the latest version of php.

BDKR

Which version of php are you using? What works for me is on version 4.2 is...

$_SERVER[argc]

This will give you the number of arguments. Use argv if you need to get at the particular args.

Later on,
BDKR

elfynmcb

Hey,

There's always the chance that your host (if you have one) has disabled the register_argc_argv php.ini option. Take a look at the output from phpinfo() to see what it's set to.

louash

Originally posted by BDKR
Which version of php are you using? What works for me is on version 4.2 is...
$_SERVER[argc]
This will give you the number of arguments. Use argv if you need to get at the particular args.

Later on,
BDKR [/B]

Ah. ok. Now if I do:

var_dump($_SERVER[argv]);

I get the array printed, so I'm now barking up the right tree, the question is, how do I use the variables in the array?

BDKR

Well, what you do with it is up to you isn't it? Seriously, that depends on what the application needs. If the application doesn't need any arguments, the why worry about the $_SERVER[argv] array right?

As an example, I wrote a load balancer that takes one argument. It needs to know database the person is using. So, you type in from the command line...

phatbalance.php postgsql

.... Then the application reads that I want to use Postgres and takes it from there. It will also check that the db is supported, not to mention wether or not the argument is even present.

Later on,
BDKR

louash

Thats all I need, one variable passed to an external script. I am working on an SNMP polling engine and I need to spawn 10 copies of the same script, each getting an ID number passed to it.

It would be helpfull if the php documentation was up-to-date.

BDKR

Originally posted by louash
It would be helpfull if the php documentation was up-to-date.

Yeah, I hear what you're saying. I had to go through phpinfo with a fine tooth comb!

Later on,
BDKR

louash

Should someone else have to do something like this, here's what I finally came up with (thanks to BDKR for the point in the right direction)

$what = $_SERVER[argv];
array ($what);
if (!$what[1])
{
 die;
} else {
DO_SOME_STUFF_WITH($what[0]);
}

Works perfectly for me