PHP problems..(Undefined Variables)

[Mark]

http://4.65.32.70/IF/main.php?page=links

at the bottom of the links page, it has undefined variables, i am hosting that site from my computer, and i know its not a problem with the actual php script, because i originally had it on a web host, and it worked fine with no such error. but when i moved it to my computer these Undefined Variable errors appear, i'm thinking its a problem in the php.ini file, but.. i have no clue, i'm a retarded newbie. help?😕 😃

[hand]

Newer php versions produces warnings in the case of "undefined variables". You can deactivate all warnings directives at runtime http://www.php.net/manual/en/function.error-reporting.php
with: error_reporting = E_ALL & ~E_NOTICE

Or you can define all used variables at the beginning of every script:

if (!isset($var1)) {
   $var1 = "";
}
$var2="";
$var3="";
// ...

[Mark]

🙁 sorry i'm stupid, so... what would i do? 😕

[assane]

Your have probably a message like this :

Notice: Undefined variable: varname in c:\inetpub\wwwroot\asssane\file.php on line 135

with varname the name of your undefined variable .
before the line 135 for example or at the begining of your page your have to write this:

if (!isset($varname)) {
$varname="";
}

that's that you have to do. Hope you 'll understand
Execuse my english.

[Mark]

i just put this inside the script and it got rid of the errors.. i dont know why, but it did 😛 :-D

error_reporting( E_ERROR | E_WARNING | E_PARSE );

[dgrinberg]

With that line of script you are just telling the parser what messages to display.

In effect you are just covering up, what could become an error.:mad:

It is telling you that you are trying to use an undefined variable, this means that what ever you are trying to do will probably not work as you intend.

You should really try and figure out in your scripts if the variable is defined (by using isset) or define it (assigning it a value). It really will make your script easier to debug and use.

[Mark]

<?
$max=100;
$dataarray=file("file.txt");
$httpcounter=0;
$empty="empty\n";

for($i=0; $i<=count($dataarray); $i++){
if($dataarray[$i] != $empty){                 //line 40
echo "<hr width=\"75%\"><br>";
$tok = strtok($dataarray[$i],":");
while($tok){
	if($httpcounter==1){
	  echo "<a href=\"http://$tok\" target='_blank'>[url]http://[/url]".$tok . "</a><br>";
	  $httpcounter++;
	} else {
	  echo "$tok<br>";
	  $httpcounter++;
	}
	$tok = strtok(":");
}
$httpcounter=0;

} 

}



?>

it says the error's are on line 40 and 43, now.. what would i do about that? with out just covering it up with error_reporting( E_ERROR | E_WARNING | E_PARSE ); 😕

[hand]

Productive servers: If you have the possibility to customize php.ini, set

error_reporting	=	E_ALL & ~E_NOTICE & ~E_WARNING 

Test- development servers: If you have the possibility to customize php.ini, set

error_reporting	=	E_ALL & ~E_NOTICE

Otherwise you can set these options at the beginning of the script:

<?
error_reporting(E_ALL & ~(E_WARNING | E_NOTICE ));
// ...

http://www.php.net/manual/en/features.error-handling.php
http://www.php.net/manual/en/function.error-reporting.php

If you get errors, please post the error messages, "it says the error's .... " is too less information, Thx