age in days/hours/minutes/secs...

kemu_

is there a easy way to get how long its been since a certain moment in days/hours/etc...

i.e.
Dated: 18/08/2002 22:55
[5 days 1 hour 48 minutes 46 seconds ago]

mrmufin

If there's a more eloquent way of doing this, I'd sure like to know; but here goes:

// get the number of seconds since 2:35:00 on August 12, 2002:
$seconds = time() - mktime(2,35,0,8,12,2002);

// determine the number of *whole* days since then:
$days = (int)($seconds / (60 * 60 * 24));

// get any remainder:
$r = (int)($seconds % (60 * 60 * 24));
if($r) {

    // the number of hours is the remainder divided by 3600:
    $hours = (int)($r / (60 * 60));

// get any remainder from the hours:
$r = (int)($r % (60 * 60));
    if($r) {
	// get the minutes:
            $minutes = (int)($r / 60);
	// what's left over is the seconds:
            $secs = (int)($r % 60);
    }
}

echo "days: " . $days . "<br />";
echo "hours: " . $hours . "<br />";
echo "mins: " . $minutes . "<br />";
echo "secss: " . $secs . "<br />";

frigidman

Not so easy, but this is a method... you could just make this into a function you use in various apps via inclue.

//get two unix time stamps
$begindate = //some sort of unix timestamp
$enddate = //some sort of unix timestamp

//break out seconds, minutes, hours
$diff = $enddate - $begindate; 
$sec  = $diff % 60; 
$diff = ($diff - $sec) / 60; 
$min  = $diff % 60; 
$diff = ($diff - $min) / 60; 
$hour = $diff % 24; 


//to get days between:
//use this with the above to get exact time between two times
$diff = $enddate - $begindate;
$daysinclusive = ceil($diff / 86400);
$daysbetween = floor($diff / 86400);

I'm sure there may be an easier way ... but I've always used the above in a function call in a common include file of personally built functions. So I never bothered to find an easier way 😃 Maybe we both can benefit from other's responses?

frigidman

Gosh durnit mufin! Again foiled by posting at the same time!! It's a conspiracy I tells ya!

jc94062

Well, I think those will work, but the easier way I find it to use PHPs own date function and then format the output as you want it...


<?

$now = time();
//format is hour, min, sec, month, day, year
$old_date = mktime(22,55,00,08,18,2002);

$difference = $now - $old_date;

$day = date(d,$difference);
$month = date(m,$difference);
$year = date(y,$difference);
$hour = date(H,$difference);
$minute = date(m,$difference);
$second = date(s,$difference);
$formatted_date = "[".$day." days ".$hour." hour ".$minute." minutes ".$second." seconds ago]";

echo "Dated: 18/08/2002 22:55"; 
echo "<br>".$formatted_date;

?>

Code can be seen in action: http://www.eliteguard.co.uk/test2.php

(Okay, so maybe it needs tweeking if you don't like 06 hours etc... but you get the idea)

Edit - Hmm, actually its really easy to make it look like what you want, just look up date to get the right letters and all, plus you don't need $year, if you can't tell the code above is just edited code I wrote months back 😃

mrmufin

We'll I'll be a mofo, jc94062!

That is much cuter than my example. Yo da man, man! (Uh, unless yer not a man, that is...)

mrmufin has been upstaged!

Weedpacket

Fine, I'll just replace half-a-dozen lines of jc94062's code (and correct the syntax):

list($year, $month, $day, $hour, $minute, $second) = explode('|', date('y|m|d|H|i|s',$difference));

(No-one uses '|' to write dates in their locale, do they?)

But I'd actually consider the arithmetic -based one sooner - it depends on if I want "122 days" or "4 months".

jc94062

What exactly is wrong with my syntax?

It works just fine, see the link!

And the reason for the "weird" output, was thats how kemu_ wanted it in his first post 🙂

kemu_

Originally posted by Weedpacket
Fine, I'll just replace half-a-dozen lines of jc94062's code (and correct the syntax):
list($year, $month, $day, $hour, $minute, $second) = explode('|', date('y|m|d|H|i|s',$difference));
(No-one uses '|' to write dates in their locale, do they?)

But I'd actually consider the arithmetic -based one sooner - it depends on if I want "122 days" or "4 months".
[/B]

the 122 days-version would be better... so it wouldnt go to months after 31 days...

jc94062

Ah, I didn't realise you wanted loads of days instead of splitting it into months.

The thing with the "math" version is that it doesn't deal with leap-years, so if you've got anything over 365 days, it may become slightly inaccurate, depends how accurate you want it to be.

If you want it really accurate, work it out like I said, then from the current month, work out which months have been counted, if its September, and you've got 3 months, then thats June, July and August, so thats 30+31+31 = 92 days 😃

Required more work, but for dates that are over 365 days it'll make it more accurate, as each year actually have 365.24999 or something days, its meant to be 365.25, but due to the occasional 4th year not being a leap year its actually slightly less, trust me, I've tried writing my own date statment and its not easy to get it right.

As I said, really depends if the odd 6 hours matters.

Edit - Forgot something again, obviously if your doing it the really accurate way and you have to count February, you need to know if its got 28 or 29 days, I don't know the foolproof way, but for 99% of years, if its divisble by 4, its a leap year, so use mod on it:

<?
function leapyear ($year)
{
	if ($year%4=='0')
	{
		return $year." is a leap year";
	}
	else
	{
		return $year." is not a leap year";
	}
}

echo leapyear(1997);
echo "<br>".leapyear(2000);

?>

Effect of this code at http://www.eliteguard.co.uk/test3.php