yeps... I knew that

Yaak

... and so, back to my original question:
Is there a way in PHP to check if a form field exists (that is: if it is submitted or not?)

malbera

if (isset($_POST['submit'])) {
//the form was submitted
}
else {
//the form wasn't submitted :D
}

dnszero

The info you're requesting should be reported by isset(), like in the example by malbera, but maybe it would be easier in the long run to try another alternative.

You could have a third radio button ("none") set as the default so that it would always be assigned a value. This would also be really easy on the backend since you already have a switch statement setup (at least your example from the other thread had one).

This would also have the added advantage of letting you easily double check form input on the server side (in addition to any javascript you do on the client side).

I know that's not exactly what you asking for but, sometimes that's the best time to look for different strategies.

Yaak

... I know the form is submitted, so the code will always execute, but what I don't know is if any radiobutton was selected.
I have tried the isset() function with the form field but to not success...
Error returned by PHP:

Parse error: parse error, unexpected T_ISSET

Yaak

Is there a function, method,.... that can tell me the number of fields that were submitted by a form?
If that would exist I could loop trough them and see if the name of each field would be what I'm looking for (that is, if something like a name attribute/property exists)

pnoeric

yaak, all submitted fields are in the $REQUEST array (or if you want to get more specific/secure, use $GET or $POST depending on the form method) ....you can do a sizeof($REQUEST) to get the number of submitted fields, but you probalby odn't need that figure; just step through the fields:

foreach($_REQUEST as $k => $v) {
echo "key $k is value $v <br>";
}

best
Eric