grab parameter through exec of php script

[badboy]

How can I exec another php script while passing a parameter and then grabing it inside the executed php script ?

Tried the following:
exec("/usr/bin/php path/script.php $parameter");
The script executes alright but I can't seem to grap the passed parameter

inside the execute script, the following does not work:
$myvar="$parameter[0]";
$myvar2="$parameter[1]";
var[$parameter];
$var[parameter];

Many thanks,
Peter M.

[pnoeric]

peter - pass it as a GET-style variable:

exec("phpscript.php?var=abc");

and inside your screipt, you grab it as $_GET['var'];

-eric

[badboy]

Eric,

I tried it and did get anything so I probably don't understand what you said.

"peter - pass it as a GET-style variable:

exec("phpscript.php?var=abc");

and inside your screipt, you grab it as $_GET['var'];
"

I tried to pass it as a get but it won't execute at all.
So I tried the following which executes but I can't grab the var:

$var="test";
$execute="/home/myaccount/special/sda51.cgi";
exec("/usr/bin/php $execute $var");

Tried to the following without any results:
$var1=$var['0'];
$var1a=$var['1'];
$var1b=$var['2'];
$var1c=$var['3'];
$var1d=$var['4'];
$var2=$var['var'];

Any Ideas ?
Thanks,
Peter

[pnoeric]

Peter, hmm... I just realized... just read this:
http://www.phpbuilder.com/columns/darrell20000319.php3

page 2 seems to have everything you need.

best
Eric