Quote Problem???

rapmonkey

Hi, could someone please tell me what is wrong with this line of code? I get an error on this line when I run it. I think it is a quote problem.

echo "<b><a href="viewnews.php?newsid=".$row['newsid'].""><font color="#FFFFFF">".$row['newstitle']."</a></b></font>"; }

ppatwari

Try:

echo "<a href=viewnews.php?newsid=" . $row['newsid'] . " >" . $row['newstitle'] . "</a>"; }

rapmonkey

it still didnt work. 🙁

Here is the PHP code I have. The rest is HTML:

<?php

$query = "SELECT * FROM newnews ORDER BY date DESC LIMIT 1";

$result = mysql_query($query) or die("Could not store database info in temporary results.");

while($row = mysql_fetch_array($result, MYSQL_ASSOC)){ echo "<font color="#FF9900" style="font-size: 15pt"><a href="viewnews.php?newsid=" . $row['newsid'] . " ><font color="#FF9900">" . $row['newstitle'] . "</font></a></font></b></td>"; }

?>
    </tr>
    <tr>
      <td width="400" height="1" colspan="3">
<?php

$query = "SELECT * FROM newnews ORDER BY date DESC LIMIT 4";

$result = mysql_query($query) or die("Could not store database info in temporary results.");

while($row = mysql_fetch_array($result, MYSQL_ASSOC)){ echo "<b><a href=viewnews.php?newsid=" . $row['newsid'] . " ><font color="#FFFFFF">" . $row['newstitle'] . "</a></b></font>"; }

?>

When I run it, I get this error: Parse error: parse error, unexpected $ in /home/t/a/tattwo/public_html/gaminglabs/gamecenter/indexnews.php on line 47

Weedpacket

Originally posted by rapmonkey
Hi, could someone please tell me what is wrong with this line of code? I get an error on this line when I run it. I think it is a quote problem.
echo "<a href="viewnews.php?newsid=".$row['newsid']."">".$row['newstitle']."</a>"; }
[/B]

Yes, it's a quote problem - your own syntax highlighting is telling you where.

echo '<b><a href="viewnews.php?newsid='.$row['newsid'].'"><font color="#FFFFFF">'.$row['newstitle'].'</a></b></font>';