how to pass a parameter with exec function

I would like to use exec to execute another PHP script while passing a parameter and cath it inside the executed script.

Tried passing it as a get variable as follows but it doesn't execute:

$var="test";
$execute="/home/myaccount/special/sda51.cgi?var=$var";
exec("/usr/bin/php $execute");

The following executes but I haven't been able to cath the $var parameter:

$var="test";
$execute="/home/myaccount/special/sda51.cgi";
exec("/usr/bin/php $execute $var");

This didn't produced any results !
$var1=$var['0'];
$var1a=$var['1'];
$var1b=$var['2'];
$var1c=$var['3'];
$var1d=$var['4'];
$var2=$var['var'];

Does anyone have any ideas on how to cath the $var

Thanks,
Peter

hi badboy,
use: exec("/usr/bin/php -q $execute $var &");
not: exec("/usr/bin/php $execute $var");

you vars are in the array $argv
$argv[0] contains the string "home/myaccount/special/sda51.cgi"
a$rgv[1] contains the string "test"

the first thing after the php-tag you must do in sda51.cgi is collecting your vars from $argv;

greetings, tijger

Tijger,

I knew I had it all wrong but didn't know where to find the answer.

Thank you very much !

Badboy

$argv dun seems to work with win32, any other alternatives?