Problems when creating a session in one window and continues in another

[smalband]

I have a page in a main window where you click on a link that opens a small login window. There you fill in name and password, which are compared to the database and if everything's correct the login window closes and a new page opens i the main window.

Now, I want sessions for this, so that I on the new page can check whether the user has actually logged in and not just stumbled upon the "right" page.

Though PHP doesn't feel like doing as I want it to.

The first time I log in, it seems as the sessions variable isn't registered and I get a "wrong login" on the new page. But if I go back and try again, it works perfectly fine. When I close the browser and start it up again the same thing happens again.

In the login window I've got this code:

if (isset($_POST['login'])) { 
   mysql connections are made here 

   if (!($row = mysql_fetch_array($result))) { 
      usch(); 
   } else { 
      session_start(); 
      $_SESSION['session_id'] = $row['id']; 
      duktigt(); 
   } 
} else { 
                form is showed.
} 

duktigt() starts a javascript that closes the login window and opens the page main.php in the main window (the window from where you opened the login window).

In main.php it says:

session_start(); 
if (!isset($_SESSION['session_id'])) { 
   echo "you'll have to try harder than that"; 
} else { 
                all the fun stuff 
}

Can't really see what's causing this..

[piersk]

Try:

<?php
if (isset($_POST['login'])) { 
   mysql connections are made here 

   if (!($row = mysql_fetch_array($result))) { 
      usch(); 
   } else { 
      session_start(); 
      $HTTP_SESSION_VARS[id] = $row['id']; 
      duktigt(); 
   } 
} else { 
                form is showed.
} 

You should notice that instead of using "session_id" as my variable, ive used just id, since session_id is a function and you/PHP might get confused.

Also, Ive used a different way of expressing the variable...

[smalband]

It's the same as before. First attempt results in failure. Pressing the back button, opening the login window again and doing the same thing as before results in success..