Variable for "if" statment as expression?

[pocka]

Is it possible at all to pass variable to "if" statment as expression?
Example:
...
$expr = "$a == $b";
if ($expr) { // this line should be taked by parser as "if ($a == $b) {"
...
}
...

[thefury]

$a = 1;
$b = 1;
$expr = ($a == $b);
if ($expr) {
true
}

[pocka]

Thanks, it really works.

[the_Igel]

Originally posted by thefury
$a = 1;
$b = 1;
$expr = ($a == $b);
if ($expr) {
true
}

It's no way different from
if ($a == $b) {},
here's no passing as variable.
Maybe trick one may need is
if (eval($expr)) {}.