eregi simple problem

[zenon]

if (eregi('^{[(/tr)(l)(f_gd_)]',$proc))}
echo "OK<br>";

I wanted to check if $proc starts with 'tr' or 'l' or 'f_gd' ;
why eregi return true if proc = 'GESTIONE_DOC_PERSONALI' ?

thanks

[mrmufin]

preg_match() is typically faster than ereg() (that's per the PHP manual). Try something like:

if(preg_match("/^tr_|l_|f_gd/i",$proc)) {
        echo "Yep, it matches";
}

[zenon]

Thanks!!! I don't know why eregi doesn't do it's job well...
example:

$proc = 'GESTIONE_DOC_PERSONALI'

if (eregi('^[(/tr_)(l_)(f_gd_)]', $proc))

result true, but should be false

[code=php]if (eregi('^[(/tr_)(l_)]',$proc))

[/code]
result false, and it's ok

in the fact, f_gd_ cause the eregi to return true I don't know why

[mrmufin]

eregi() does its job fine; it's your match string that's suffering. The '|' is the 'OR' seperator with reg_exps:

if(eregi("^(tr_|l_|f_gd)",$proc)) {
	// should work as well, but preg_match() is usually faster
}