exclude specific files from being displayed

[[deleted]]

I'm getting a feed from a partner's web site. His site is formatted specifically for his needs including images.

I'm using
$html = file("http://www.remoteserver.com/directory/index.html") or die("Could not
load
remote HTML");
echo implode('', $html);
to grab the page and display it on my site. I want to be able to programatically exclude specific image file names. Also, he has TR tags specified to a color inconsistent with my PHP Nuke theme. Is there a way to change the TRs background colors without change the TR background colors for the theme?

Thanks.

[the_Igel]

why not

$bad_names = '(bad_name|another_bad_name|one_more_bad_name)';

foreach ($html as $string)
{

$string = preg_replace('#<img src="'.$bad_names.'">#i', '', $string);
$string = preg_replace('#<tr bgcolor=.*?>#i', '<tr>', $string);
}

Of course, it's simplyfied example, but you can enhance it.

[[deleted]]

<?php

/*********************************************************************/
/ PHP-NUKE: Web Portal System /
/ =========================== /
/ /
/ Copyright (c) 2002 by Francisco Burzi /
/ http://phpnuke.org /
/ /
/ ===================== /
/ Base on Reviews Addon /
/ Copyright (c) 2000 by Jeff Lambert ([e-mail]) /
/ http://www.qchc.com /
/ More scripts on http://www.jeffx.qchc.com /
/ /
/ This program is free software. You can redistribute it and/or modify /
/ it under the terms of the GNU General Public License as published by /
/ the Free Software Foundation; either version 2 of the License. /
/*********************************************************************/

if (!eregi("modules.php", $PHP_SELF)) {
die ("You can't access this file directly...");
}
require_once("mainfile.php");
$module_name = basename(dirname(FILE));
$index = 1;

include ("header.php");

$html = file("http://www.remoteserver.com/remotedirector/file.html") or die("Could not
load
remote HTML");
echo implode('', $html);
$bad_names = '(service_head.gif|logo.gif|stripes-06.gif|coaching-over.gif|conventions-over.gif|stripes-11.gif )';

foreach ($html as $string)
{

$string = preg_replace('#<img src="'.$bad_names.'">#i', '', $string);
$string = preg_replace('#<tr bgcolor=.*?>#i', '<tr>', $string);
}

?>

This did not remove any of the $bad_names. Any other thoughts.

[DigitalExpl0it]

how about somthing like this... code is on the page...Click

[url]http://www.daemonprojects.com/fun/getsource.php[/url]

[[deleted]]

I made some changes trying to use the ereg_replace() function, but still no lucl.

if (!eregi("modules.php", $PHP_SELF)) {
die ("You can't access this file directly...");
}
require_once("mainfile.php");
$module_name = basename(dirname(FILE));
$index = 1;

include ("header.php");

$html = file("http://www.remoteserver.com/index.html") or die("Could not
load
remote HTML");
echo implode('', $html);
$bad_names = '(service_head.gif|logo.gif|stripes.gif|logo2.gif|image3.gif|image4.gif )';

foreach ($html as $string)
{

$string = ereg_replace('#<img src="'.$bad_names.'">#i', '', $string);
$string = ereg_replace('#<tr bgcolor=\".*\">#i', '<tr>', $string);
}

[the_Igel]

What do you want to get, when you do checks after you do the output?!!

And, foreach is for array, not for string.

You have to do it this way:

$html = file(.....);
$bad_names = '(....)';

foreach($html as $string)
{
...................
}

echo implode('', $html);

It will cause problems, though, in case there are some tags in source file that start on one line and end on another.

[[deleted]]

How about doing an If statement looking for a specific condition then doing a replace.

So, something like this:

$html = file("http://www.remoteserver.com/index.html") or die("Could not
load
remote HTML");

$tr = "<tr bgolor=\"teal\">";
if ($tg !=""){
ereg_replace('$tg', '<tr bgcolor=\"#FFFFFF\">');
}
echo implode('', $html);