Default value on function

[Phpdiot]

Hi, I've a function which consist of 5 arguments.

function make_checkbox_html($arr, $num, $width, $name, $checked) {

$i = 1;
  if (isset($checked)) {
    /* if we passed in an array of the checkboxes we want 
       to be displayed as checked */ 
    foreach ($arr as $ele) {
      $str .= "<td><input type=\"checkbox\" name=\"$name\" value=\"$ele->id\"";
      foreach ($checked as $entry) {
    if ($entry == $ele->value) { 
      $str .= "checked";
          continue;
        }
      }
      $str .= ">";
      $str .= "$ele->value";

  if ($i % $num == 0) {
    $str .= "</tr>\n<tr>";
  } else {
    $str .= "</td>\n";
  }
  $i++;
}

  } else {

The $checked was meant to be default but I get an error Warning: Missing argument 5 for make_checkbox_html() when I tried to use this.

$available = make_checkbox_html($favorites, 3, "100%", "favorites[]");

Any help?

[bernouli]

you need 5 (five) arguments in order to use make_checkbox_html

function make_checkbox_html($arr, $num, $width, $name, $checked)

but you use only 4 (four) arguments which comes to error

$available = make_checkbox_html($favorites, 3, "100%", "favorites[]");

[Phpdiot]

i know, but I use this tut:

http://www.phpbuilder.com/columns/laflamme20001016.php3?page=3

How come? Thanks

[bernouli]

try to change

function make_checkbox_html($arr, $num, $width, $name, $checked)

into

function make_checkbox_html($arr, $num, $width, $name, $checked=array())

[Phpdiot]

Thanks alot bernouli!