HTTP_POST_VARS and global variables

joice

I have a problem which I hope I can describe right here. First of all let me say that I am an ASP developer learning PHP, so the solutions I come up with are usually ASP-solutions I want to code in PHP...
The problem is, I have a form with checkboxes:
<input type="checkbox" name="all" <? if($all!=""){echo"CHECKED";}?>>
<input type="checkbox" name="name" <? if($name!="" || $alles!=""){echo"CHECKED";}?>>

etc. etc.
Now, what I want is that when I visit the page for the first time, the all-checkbox is checked and therefore used in the query that follows this code. Therefore I have to set the all-variable the first time someone enters the page (let's say I set it to "on").
Now when I am on the page and I decide to uncheck the box, I don't want the all-checkbox to be used in the query after I post the form.

My problem is that if I print the all-variable on the first line of the page, the first time I enter the page, the variable is on. But since variables are global in PHP, it stays on, so even if I uncheck the box, it stays on after posting the form.

To avoid using global variables, I used

if($HTTP_POST_VARS["all"] !="on"){
$all="";
}

but this does not seem to work. :o

Now in ASP I would use request.form("all") and that always works... does $HTTP_POST_VARS work in the same manner?

Joyce

Bunkermaster

Originally posted by joice
... First of all let me say that I am an ASP developer learning PHP...

Welcome to the bright side of the force 😃

Originally posted by joice
Now in ASP I would use request.form("all") and that always works... does $HTTP_POST_VARS work in the same manner?

Yes

Do you have a $all variable in your form script? If yes test if it is intialized before testing for a value

if (!isset($all) & $all = "on"){ 
echo "CHECKED";
}

maybe a display of the value of all at different levels in the script would be a good idea...

joice

I am about to find out if this really is the bright side of the force 😉

My code is like this now :

<...>

$all=="on";
if($HTTP_POST_VARS["all"] !="on"){
$alles="";
}
?>

<...>

<FORM method=post action=index.php?>
<input type="checkbox" name="all" <? if(!isset($all) & $all!=""){echo"CHECKED";}?>> <I>Select all</I>
</FORM>

<...>

<?PHP
if($all!=""{
echo"<TD ALIGN=middle><FONT FACE=Arial,Verdana,Helvetica SIZE=2 COLOR=#000000>All</FONT></TD>";
}
?>

So what I want is that the first time I visit the page, the TD mentioned above is printed. Then, if I uncheck the box and post the form, I don't want the TD printed. The actual problem at the moment is that the TD is not printed at all, the first time I visit the page....

Joyce

Bunkermaster

before it works you might check for structure probs in your code

Originally posted by joice
<...>

$all=="on"; //<-- argh! == not good this is not a comparision
<...>
if($all!=""{//<-- argh! you might concider closing the parenthesis
<...>

joice

The first = is gone now, the second issue was just a copy-paste-mistake, it is alright in the code...... but it still does not work.

Joyce

Bunkermaster

you have a strange bit up there in your code... everytime you exec your page you set $all to on so why should it not be?

<...>
$all=="on";
if($HTTP_POST_VARS["all"] !="on"){
$alles="";
}
?>

<...>

IMHO it should be :

<...>
if (!isset( $all)){
$all="on";
}
if($HTTP_POST_VARS["all"] !="on"){
$alles="";
}
?>

<...>

that way you avoid to reset the variable each time you call the page wether it IS set or not