Passing arrays to functions

[V0oD0o]

Hello,

Is there a special way to pass arrays into functions? As I get "Missing argument 4 for getimage()"

$retVal is the array.

    

//This fucntion works out what the next/prev images are.
  function getImage($direction, $count, $current, $imgArray){
   if ($direction == "prev"){
    $image = --$current;
      if ($image <= 2) {
        $image = 2;
      }
      if (!$blah = (isImage($imgArray["$image"]))){
        $image = --$current;
       }
   }
   if ($direction == "next"){
    $image = ++$current;
      if ($image > $count){
        $image = $count;
      }
      if (!$blah = (isImage($imgArray["$image"]))){
        $image = ++$current;
       }
    }
    return $image;
   }

and this is how I am calling the function:

$no = getImage('prev', count($retVal), $page, $retVal);

Thanks in advance,

Mike

[mayus]

perhaps perform th count before the routine call :

$count = count($retVal);

getImage('prev', $count, $page, $retVal);

[V0oD0o]

Thanks,

Got that just before I came back here. 😉

Cheers,

Mike

[thom]

What seems to me to be a better solution is to perform count($retVal) inside the function:

function getImage($direction,  $current, $imgArray){
$count = count($imgArray);
....

because the function is something you will only write once but otherwise you have to do this count() thingy everytime you use the function.

regards,
thom

[mayus]

You are right but it depends on whether the $count is to be used elsewhere after the routine call.

Base on the original post I don't think so.

Mayu

[V0oD0o]

Thanks for all your help guys.

I shall make those ammends.