Simple use of eregi_replace NOT working!!!!

aaronzoller

I'm trying to do what should be a simple regular expression replace. Can anyone explain to me why this does not work...

<?php

$str = "<A HREF=\"http://www.blah.com/blah.htm\">";

$newstring = eregi_replace("<A HREF=\"(.+)\">", "<ANCHOR>\1</ANCHOR>", $str);

echo $newstring;

I want to get the address in between the <ANCHOR> </ANCHOR> tags. Like this:

What the heck am I doing wrong?

mark_and_co

Hi,

I've never done anything like this, but I do understand what you're trying to do. THe only thing I can see that MAY be incorrect is the '(.+)'. I've not seen this before, but I'm not certain it's incorrect. The best one i can recommend is:
eregi_replace("<A HREF=\"(.)\">", or
eregi_replace("<A HREF=\"[^>]\">", .

Hope this helps

Mark

jernhenrik

I dont get it? The outout u want is?

http://www.blah.com/blah.htm

yes??

Errr it works for me with the code u posted??

sorry if i misunderstand

mark_and_co

Hi,

Glad it worked... PHEW

Mark

jernhenrik

Originally posted by mark_and_co
Hi,

Glad it worked... PHEW

Mark

Errr hehehe actually i meant with the code that aaronzoller wrote
😃

havent tried it with yours Mark 😉

mark_and_co

Oh... OK

Serves me right for not looking who posted that.
I bow my head in shame

AZ3

Mark_and_co rocks!!!

eregi_replace("<A HREF=\"(.*)\">", blahblahblahblah

WORKED!!!!

YAY I am SO SO SO VERY HAPPY.

Aaron Zoller

😃

mark_and_co

I now hold my head up high
🆒

Glad to help.
Mark

Weedpacket

What if there are two links in the string being examined?

The only difference between . and .+ is that the latter requires at least one character to be matched. In other words, the difference is that . allows <a href=""> and .+ doesn't.

I'd've used '<A HREF="([^"]+)">' as my regexp string - this doesn't allow empty links either, and also works if there is more than one link in the string. It does require href attribute values to be enclosed in double quotes, however.