displaying results in a table

[robsgaming]

I am trying to display results in a table ... how would it do so side by side...

example of the code below

there is code before this, just showing below as the example..

echo "<table>";

while ($row = mysql_fetch_array ($result)) {
extract($row);

echo "
<tr><td>$img</td><td>$img</td></tr>
</center>
";

}
echo "</table">;

of course, this is givng me the vaule of $img twice the same on each row in the table.. how do i fix it to where it shows it side by side?

does what im asking make sense? lol... thanks for any help.

[the_Igel]

as far as i understand your question, try

$left = 1;
echo '<table>';

while ($row = mysql_fetch_array ($result))
{
if ($left) echo '<tr><td>'.$row['img'].'</td>';
else echo '<td>'.$row['img'].'</td></tr>';
$left = !$left;
}
if (!$left) echo '<td>&nbsp;</td></tr>';
// odd number of $rows
echo '</table>';

[robsgaming]

Thank you for the help --- it worked fine.