FORMS in side PHP

dcjones

Hi all,

HELP, again

I have a script which contains a table and inside the table there is a form. I get the error😛arse error: parse error, expecting ','' or';''

This error is reported to be at line 93, line 93 in the script is the part which starts with: <input type

this is the code I am using, is it correct,

"\n\t<th width=\"15%\" bgcolor=\"#cccccc\"><font color=\"black\" size=\"-2\" >
<form>
<input type="button value=" name="Open the Popup Window" onClick="javascript:popUp('test')">
</form></th>" .

Many thanks in advance

Dereck

stuartc1

Looks like an easy one....

insert a ; at the end of the statement like this:

"\n\t<th width=\"15%\" bgcolor=\"#cccccc\"><font color=\"black\" size=\"-2\" > 
<form> 
<input type=\"button\" value=\"\" name=\"Open the Popup Window\" onClick=\"javascriptopUp('test')\"> 
</form></th>";

you also apear to have a few " that havnt been escaped correctly.

floR

You have forgotten to escape (\") the " characters in your <input> tag.

make it like this:

dcjones

Hi Again

Had 2 suggestions. done both. still the same error:

the code now looks like this

"\n\t<th width=\"15%\" bgcolor=\"#cccccc\"><font color=\"black\" size=\"-2\" >
<form>
<input type="button\" name=\"Open the Popup Window\" onClick=\"javascript:popUp('test')\">
</form></th>";

Any more ideas

Thanks

floR

Ouch, my fault. There's still one " unescaped:

type=\"button\"

dcjones

Sorry guys, my mistake, it now works thanks for your help

Dereck