this should work:
echo ('<select name="c_council">');
$sql = "SELECT c_council_id FROM dropdowns";
$results = mysql_query($sql);
while ($row=mysql_fetch_array($results,MYSQL_ASSOC)) {
if (strlen($row['c_council_id']) > 0) {
echo "<option value=" . $row['c_council_id'] . ">" . $row['c_council_id'] . "</option>\n";
}
}
echo ('</select>');
why were you selecting the same column twice (c_council_id) from the database table (dropdowns)? well I changed that, and I added an "if" loop that makes sure the row contains a value, and if it doesn't its skiped. Hope this helps. I haven't tested the code, so there could be a syntax problem, but I looked it over pretty good.