preg_replace ();

[lordgreg]

help me with this one

$box_search = array (
  "'{%lang.(.*?)}'i",
);

$box_replace = array (
  $lang ['\\\\1'],
);

$boxput = preg_replace ($box_search, $box_replace, $boxput);

so, if i have the text %lang.myname in the input string i run the preg_replace and it SHOULD replace it with array value for $lang ['myname'] but it doesnt!

once again:

1. $boxput = "this is the example. and ". %lang.myname ." Gregor";

2. preg_replace finds %lang.(.*?) in string.

3. preg_replace should replace that text with $lang ['\\\\1']. IT DOESN'T!!!

thanks all for helping 😉

[[deleted]]

Disclaimer: I am by no means a regular expression expert.

But, this seems to work:

<?
$boxput = "this is the example. and %lang.myname Gregor";

$box_search = array (
"/(%lang.)(\w.+)\040/i"
);
/* that strange character shouldn't be there
  it is a backslash 0 (zero) then the number 40 */

$box_replace = array (
"\$lang['\\2'] "
);

$boxput = preg_replace ($box_search, $box_replace, $boxput);

echo $boxput;
?>

[lordgreg]

it works for you?

well,.. i'm terribly sorry but it doesn't work for me 😢

[lordgreg]

it works for you?

well,.. i'm terribly sorry but it doesn't work for me 😢

[[deleted]]

Hmm..multiple back slashes seem to have been stripped..check this attached file instead....

[lordgreg]

um.. matt i'm sorry but itlooks like you didn't understood me correctly..

i want to replace %lang... with the VALUE in that array...

if $lang [myname] = "my name is "

%lang.myname will become "my name is"...

thanks 😉

[[deleted]]

Sorry about that..try this attachment..