Help! We are trying to exclude elements in the first array from printing when we filter them against the second array. In the conditional statement, if you change the != to ==, it works the opposite way fine.

Cracked out in Columbus...

$bry = array("blue","red", "indigo");
$roygbiv = array("red","orange","yellow","green","blue","indigo","violet");
$bry_count = count($bry);
$roygbiv_count = count($roygbiv);
for ($x = 0; $x <= $bry_count; $x++) {
for ($y = 0; $y <= $roygbiv_count; $y++) {
if ($bry[$x] != $roygbiv[$y]) {
echo $roygbiv[$y];
}
}
}

    first of all, your second array contains all the elements that first array does, so this should print nothing, here's a corrected example. I removed indigo from the 2nd array.

    $bry = array("blue","red", "indigo");
$roygbiv = array("red","orange","yellow","green","blue","violet");
$bry_count = count($bry);
$roygbiv_count = count($roygbiv);

for ($x = 0; $x <= $bry_count; $x++) {
    for ($y = 0; $y <= $roygbiv_count; $y++) {
        if ($bry[$x] == $roygbiv[$y]) {
            continue(2);
        }
    }
    echo $bry[$x] ."\n";
}

      Aha! Yes! Continue! Man, I think I need a new book. Both books we have around here don't include Continue. Thanks very much. Very useful!

      Marty

        You could also consider:

        $bry = array("blue","red", "indigo");
$roygbiv = array("red","orange","yellow","green","blue","violet");
$filtered_array = array_diff($bry, $roygbiv);

foreach($filtered_array as $colour)
{ echo $colour."\n";
}
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