Display Image If Field Empty?

[headsmack]

How is it possible to display a specified image if a field comes up as empty?

please be specific when replying, i am new to this.

aswell when you post the code, please state where it goes..😕

and chuckle all you want at this post!

thanks

[sfhc]

I assume that you mean form field?

It does not really matter, cuz you are checking the value of a variable from somewhere..

if(empty($someVar)){
// display image
} elseif(!empty($someVar)){
// do somethign else
}

[headsmack]

how can that be done when checking a result id (and not a field) ?

[sfhc]

If you mean the result id from a query you can do that a couple ways.

Assume $result is from the query.

if(!result){
  // show image
} else{
  // do something else
}

or

$resultArray=@mysql_fetch_array($result);
if(sizeof($resultArray<1)){
 // show image
} else{
 // do something else
}

[headsmack]

thanks!