can anyone see the error in this code?? i think its in the queryt but i just cant see it.
$query = "CREATE TABLE test (uid INT(6) not null auto_increment primary key, client_initial VARCHAR(4) not null, client_surname VARCHAR(20) not null, client_dob VARCHAR(8) not null, client_road VARCHAR(30), client_city VARCHAR(20), client_post VARCHAR(9), client_telareaone VARCHAR(6) not null, client_telone VARCHAR(6) not null, client_telareatwo VARCHAR(6), client_teltwo VARCHAR(6), client_sex VARCHAR(1), client_nin VARCHAR(9), client_marital VARCHAR(3),, client_note VARCHAR(200), stamp TIMESTAMP(14) not null, db_src VARCHAR(20) not null, enabled INT(1) not null DEFAULT '1')";
$result = mysql_query($query) or die("<center><font face='Verdana, Arial, Helvetica, sans-serif' size='2' color='FF0000'> Query failed. Mysql said: " . mysql_error() . " </font></center>");# ("<center><font face='Verdana, Arial, Helvetica, sans-serif' size='2' color='FF0000'>Query failed</font></center>");
echo "<center><font face='Verdana, Arial, Helvetica, sans-serif' size='2' color='000000'>Table - test </font><font face='Verdana, Arial, Helvetica, sans-serif' size='2' color='00FF00'>Created successfully.</font></center>";
