Displaying Information with a Select Box

Kyo

What I'm trying to do is make a script that when you select some's name from a select box it will display there information on the page.
The code I'm using for the select box fallows:

print "<table border=0>\n";

print "<tr><td>Display information on:</td>";
print "<td><select name=\"Names\">\n";

while ( $a_row = mysql_fetch_row( $result) )
{
foreach ( $a_row as $field )
print "\t<option value=\"$field\"> $field\n";
}
print "</select></td>\n";
print "</table>\n";

This gives me the Select box with all the names in the DB.

IceD

print "<table border=0>\n";

print "<tr><td>Display information on:</td>";
print "<td><select name=\"Names\">\n";

while ( $a_row = mysql_fetch_row( $result) )
{
  print "\t<option value=\"" . $a_row["name"] . "\">" . $a_row["name"] . "\n";
}
print "</select></td></tr>\n";
print "</table>\n";

Kyo

Actually I was cerious if there is a way to display someone's information from a select box.

Say the select box name has: text 1, text 2, text 3, text4

When the person selects text 3 is there a function I can use to see when the name has been changed in the text box? Or would I have to us a loop or java script.

Completly lost here 😕

levi_501_dehaan

here is one thing you can do.

 <select name="select2" size="" onChange="this.form.submit();" >

then just put the form action as <? echo $PHP_SELF; ?>
and it will change it for you 🙂

-=Levi=-

Chimera

You would have to use Javascript, since the user selecting their name is performing a client side action. Something like :

<select name="Names" onChange="alert('The selected name is '.document.FormName.Names[document.FormName.Names.selectedIndex].value);">

Obviously you wouldn't want to just display an alert with the name, you would need to perform a different action (probably a location.href) and pass the selected name.