$result = 2

keakathleen

Does anyone know what is wrong with your code when the $result = 2?

A little from my code so you know how I am using $result...

//set up the command
$command = "gpg -a --recipient 'angela' --encrypt -o $outfile $infile";

//error finding code
echo "this is the outfile: ".$outfile."";
echo "this is the infile: ".$infile."";
echo "this is the command: ".$command."";

//execute the gpg command
system($command, $result);

echo "this is the result: ".$result."";
THE RESULT HERE EQUALS 2.

I am wondering if my gpg command is not executing because I am not in the right directory. I am echoing everything to the screen so that I can debug but I cannot see anything wrong with the echoed results. Of course, the result needs to equal 0 before my code executes right. Any suggestions?

bastien

ie if the result equals 2 then

if ($result==2){
//do somthing
}else{
//do somehting else
}

you will need to use the two equal signs (==) to do a comparison

one equal sign forces the $result to equal 2

hth

michael

$result = system($mycommand, 1);
IF ($result) {
// echo success
}

keakathleen

According to my above code:

system($command, $result);

My result is automatically stored as a result of my command. If my command executes properly then my result should be 0. My result is 2. I cannot make it equal 0 because my code is not running properly. What does it mean when you get a result of 2. Is there a specific error code for instance 2 means you are in the wrong directory????

😕
Ange

jeremuck

is your question in regard to the linux command or to how to handle it in PHP?
if it's the linux command, I suggest taking a look at the man pages involving the command.

keakathleen

When I was programming in MySql and PHP, I would often get a $result back from my query that was 1. I then knew that the code had worked correctly and a record had been store in my table. If the result was 0 or -1, I knew that my PHP code was not correctly working. Each of these results meant something. Like the result of 0, meant that my PHP coding and MySQL query code was correct, I just was missing a field or some minor detail. The -1 meant that my PHP code and MySql query coding was not right. For instance, an extra paranthesis or quotation mark was in the query that shouldn't have been.

I assumed that the same was true for the result when trying to run a system command. If the result was 0, your system command was satisfactory. If the result was 1, then blah, blah, blah is wrong with the command. If the result was 2, then this is wrong with your command. Do you see where I'm going? Is there any error code with the variable result that I should be aware of?

jeremuck

I see your point, however the error code was produced by the program, not PHP.
The error is the program's, not PHP's.
Therefore, the explanation of the error involves the command, not PHP.

Second, you shouldn't assume anything.

The errors that mySQL returns involve mySQL, not PHP. Yes, you can view them in PHP, but they come from mySQL. The same is true with this system command.

The only errors having to do with PHP are the errors that PHP itself generates... the Warning: errors and the Fatal Errors.

sorry to say it, but your assumption is wrong, and your question is in regard to the system command. You want to know what the return code of the system command is.

I found this:

3.6 Key signing

As mentioned before in the introduction there is one major Achilles' heel in the system. This is the authenticity of public keys. If you have a wrong public key you can say bye bye to the value of your encryption. To overcome such risks there is a possibility of signing keys. In that case you place your signature over the key, so that you are absolutely positive that this key is valid. This leads to the situation where the signature acknowledges that the user ID mentioned in the key is actually the owner of that key. With that reassurance you can start encrypting.

Using the gpg --edit-key UID command for the key that needs to be signed you can sign it with the sign command.

You should only sign a key as being authentic when you are ABSOLUTELY SURE that the key is really authentic!!!. So if you are positive you got the key yourself (like on a key signing party) or you got the key through other means and checked it (for instance by phone) using the fingerprint-mechanism. You should never sign a key based on any assumption.

Based on the available signatures and "ownertrusts" GnuPG determines the validity of keys. Ownertrust is a value that the owner of a key uses to determine the level of trust for a certain key. The values are

1 = Don't know
2 = I do NOT trust
3 = I trust marginally
4 = I trust fully

If the user does not trust a signature it can say so and thus disregard the signature. Trust information is not stored in the same file as the keys, but in a separate file.

at:
http://webber.dewinter.com/gnupg_howto/english/GPGMiniHowto-3.html

http://linux.ctyme.com/userdoc/gnupg-1.0.6/faq.html#q4.1

I suggest running your command in the command line, and seeing what it says, as the errors are outlined in the second link I posted.
I also found some stuff referring to using this command in a web environment, like you want. You might find something useful.

I'm not sure why you want to use this, but you might take a look at the encryption functions built into PHP.

keakathleen

Thanks for your help. I will refer to the GPG manual for more error coding details. I am using the script to send encrypted e-mails.