ok, I have a page, on this page it check to see if an image is present. If it is there it should print out the tumbnail and a link to the full sized image. If the thumbnail does not exist I'm tryin to get it to print out a empty table cell. I can get it to print the image if it is there but if it is not there it still print out the missing image thing.
<?PHP
//the img1 is there $img1path="secure/memfiles/Pheagey/Drone/hatchet/tmb_hatchet1.jpg";
if(!file_exists($img1path));
{
echo "
<td align=\"center\" valign=\"middle\">
<a href=\"secure/memfiles/Pheagey/Drone/hatchet/hatchet1.jpg\" target=\"_new\" ><img src=\"secure/memfiles/Pheagey/Drone/hatchet/tmb_hatchet1.jpg\" border=\"0\"></a>
</td>";
}
//image two is not there but I still get a missing image icon printed out
$img2path="secure/memfiles/Pheagey/Drone/hatchet/tmb_hatchet2.jpg";
if(!file_exists($img2path));
{
echo "
<td align=\"center\" valign=\"middle\">
<a href=\"secure/memfiles/Pheagey/Drone/hatchet/hatchet2.jpg\" target=\"_new\" ><img src=\"secure/memfiles/Pheagey/Drone/hatchet/tmb_hatchet2.jpg\" border=\"0\"></a>
</td>";
}
?>
any help is greatly appriciated.