What do you suppose this means?:
"Warning: Supplied argument is not a valid MySQL result resource"
it says that it takes place on line 11, this is line 11 in my php file:
$num=mysql_numrows($result);
any ideas? I'm reeeallyy new to php/mysql
Step back to where there is a query taking place...something like:
$result = mysql_query("select * from table where blad = $bajs");
That query is most likely not running correctly. Either the table name is wrong, or a column name is wrong, etc...
yup that did it, silly me, wrong table name
