Extracting from a $string . . . .

[Brian_A]

I have a the follwoing string combinations:

(examples)

/sigs/temp/filename.gif
/sigs/filename.gif
/sigs/backup/temp/filename.gif

How do I extract just "/filename.gif" out of each of these.

This is very difficult for me because the I need to be able to remove all sub-directory information when and the directory structure for these file(s) changes constantly.

I will definately appreciate any and all advice on this one. Thank you so much.

• Brian

[br__ken]

$info=pathinfo($file);
print_r($info);

im pretty sure you want $info['basename']

but, look at them all and see what u want

-r

[Brian_A]

This is the way that I figured it out, which btw brøken led me to however left-handedly.

This is likely the best test of what a newbie I am but it works. If there is a "cleaner" way please let me know.

$file = "/www/docs/ss/index.html";

//where $file is the name we want to remove all slashes & sub-dir's to yeild just the name.
$delims = "/";
$word = strtok ($file, $delims);
while (is_string ($word)) {
if ($word)
$word = strtok ($delims);
if ($word != "") {
$cleanedup = $word; // $cleanedup is the root file name all cleaned up.
}


echo $cleanedup;

... would yield index.html

That removes all slashes out of names like "/www/docs/ss/index.html" and yields "index.html".

Like I said, it is a newbie way but it worked.

Thanks for the direction brøken .

[br__ken]

$file = "/www/docs/ss/index.html"; 
$info=pathinfo($file);
echo $info['basename'];
// = index.html 

😃 pathinfo is very handy

[Brian_A]

See, I told you I was a newbie.

Thanks again brøken while my method worked.... WHY go to the trouble when it is NOT the best way and the method you point out is so obviously faster.

Not really a question so much an answer.

🆒