more than one button on a page

Tiger99

I have two buttons Delete and Edit
If the user click on Delete, it stays on the same page, but if the user click on Edit, it changes to another page

So, how should I use my form tag(do I need more than one)??

Please help

Thanks in advance

ednark

if you name your input...

the page you submit too will have

$_POST['action'] == 'DELETE'

$_POST['action'] == 'UPDATE'

depending on which button the user pushed..

punchline: just name your input and your fine

Tiger99

sorry I didn't get what you say

So if I have a form tag
<form action="page1.php" method="post">
<select name=id>
blah blah

if I need to pass the value "id" to page 1 when user press delete
but pass the same "id" to page 2 when user press edit

Should I have another form tag somewhere that goes to page2??

Please help

Thanks in advance

ednark

try running this script... it should show you what i meant...

<?php

print "<pre>";
print_r($_POST);
print "</pre>";

?>

<form action="./<?=$SERVER['SCRIPT_FILENAME']?>" method="post">
    <select name="id">
        <option value="A">A</option>
        <option value="B">B</option>
    </select>
    <input type='submit' name='action' value='Delete'>
    <input type='submit' name='action' value='Edit'>
    <input type='submit' name='action' value='Foo'>
    <input type='submit' name='action' value='Bar'>
    <input type='submit' name='action' value='Baz'>
<form>

Tiger99

Sorry, I ran the script and I still can't figure out what the following two lines do..

print_r($_POST);

<form action="./<?=$SERVER['SCRIPT_FILENAME']?>"

What values do I get from
$_POST
and
<?=$SERVER['SCRIPT_FILENAME']?>"

Please help

Thanks in billion

Weedpacket

Typo: $SERVER should be $_SERVER.

For an explanation of what [man]print_r[/man] does, see that link, and see here for what $POST and $SERVER are.

Tiger99

I don't understand, am I suppose to some thing that this before my form tag?

if($action=="Delete"){
$HTTP_SERVER_VARS['SCRIPT_FILENAME']="delete.php"
}else if($action=="Edit"){
$HTTP_SERVER_VARS['SCRIPT_FILENAME']="edit.php"
}etc....

However, it doesn't do what it is suppose to do.
Where did I do wrong???

Please help

Allen

ednark

$_SERVER['SCRIPT_FILENAME']

just tells you what page you are looking at...

i was making the page submit to itself... this way if you named the page something different than me the script would still work

$_POST holds all the things in a form that uses <form method='post'>

the page checks _POST to see if there is anything there.... if there is anything there you assume the user just submitted the form....

if the just submitted the form
$_POST['action'] should be set

$_POST['action'] should contain the text of the button that was pressed

depending on what button was pressed you either update the infromation or delete the information or do something else to it...

Tiger99

God, I can't believe I spent two days trying to solve this problem. This sucks so bad.
I can't believe a form can only redirect to ONE script.
I guess I need to redesign my application with only one button
🙁

This is very frastrating

Tiger99

I understand what $server and $post do.
However when I use this line
<form action="./<?=$SERVER['SCRIPT_FILENAME']?>"
it appends the same address twice
eg www.yahoo.com/yahoo.com so it always show page not found

So, I am trying to change the $SERVER['SCRIPT_FILENAME'] value or script name by determining the value of $post(button value). However, it just doesn't work because the form has to go to this page($SERVER['SCRIPT_FILENAME']) - file not found page before it gets the $post values

Please help

Thanks in advance

Tiger99

sorry it doesn't append the url
but it shows the whole path of the url (eg. some other not necessary directories) and it sill shows page not found

Weedpacket

I think $SERVER['PHP_SELF'] might be a better choice.... Use print_r($SERVER) to see what else is in there.

But as ednark noted:

i was making the page submit to itself... this way if you named the page something different than me the script would still work

So if you know what the page is called, just use that.