Problem verifying a $submit from POST

Huuggee

i'm having real difficulty with a piece of verification code to work out whether to show a form or the resultant input of the form, by checking whether a submit button has been pressed.

Problem i seem to be getting is that my $submit doesn't exist.

i have this:

if (!$submit) {
//show form
} else {
//show form data}

any one have any ideas?

SpasePeepole

if (isset($submit)) { 
//show form 
} else { 
//show form data}

Huuggee

var = 0;

if (empty($var)) { // evaluates true
echo '$var is either 0 or not set at all';
}

if (!isset($var)) { // evaluates false
echo '$var is not set at all';
}

I just found it, Thanx tho.

Just having a problem with pulling my $id var oout

:/
it's all fun!!

philipolson

This is just a FYI JIC: It's recommended to code with the php directive register_globals off. $submit will exist from <input type="submit" name="submit"> only if register_globals = on. As of PHP 4.2.0 this directive defaults to off and it's preferred to not assume it's on. See:

http://www.php.net/variables.external

jerdo

To expand on what philipolson posted. If register_globals is off, as it should be, you would access submit using either $GET[submit] or $POST[submit].

Huuggee

I understood that i have register_globals offf, and have no intention of turning them on and therefore having to use $GET['submit']
Problem i had arose from being allowed to use !$submit if globals are registered, and you cannot simply use (in the same way)
!$GET['submit'] if globals aren't registered.
Instead the use of empty() and isset() helps loads 🙂