if/else statement question

[micmac]

Hi all,
If you look at the script below how can i get the form to display if the confirm_cat is equal to "nil"?
At the moment it only displays when confirm_cat isn't equal to 'yes'.
Any ideas?

Cheers,
micmac

<?
$row = mysql_fetch_row(mysql_query("SELECT COUNT(*) FROM cat1 WHERE CatParent = $id"));
if($row[0] > 0){

$result = mysql_query("SELECT * FROM cat1 WHERE CatParent = $id AND active='yes' ORDER BY CatName");
while($row = mysql_fetch_array($result)){

    if($row['confirm_cat'] == 'yes'){

    echo "<center><TABLE width=\"400\"></center><TR><td>";
	echo "<p align=\"left\"><a href=\"add_url1.php?id={$row['CatID']}&country=$country\">{$row['CatName']}</a></p>";
    echo "</TR><center></table></center>";	    }
	}
	} else {
	?>

<form method="post" action="<?php echo $PHP_SELF?>">

HTML form here.............      

</form>

<?	
}
}
?>

[the_Igel]

if ($confirm == 'yes') {

// do something

} elseif ($confirm == 'nil') {

// do something else

} else {

// or maybe something for any other case

}

[bobthedog]

if (($row['confirm_cat'] == 'yes') || ($row['confirm_cat'] == 'nil'))
{

.... blah blah