Converting a string to 2 decimal places ....

[benbox]

Hi,

printf("%.2f", $value) ;
will print $value with 2 decimal points...

but how can I get this value into a variable?

so for example,
if $value was 33.5
it would make $value = 33.50

thanks in advance
Ben

[wizkid]

Hi,

try following:

$n = 12.3;
echo number_format($n, 2);

wizkid

[benbox]

Wohoo! Thanks wizkid! 😃

[ctheun]

From what I understand is that the new value should be whatever printf made the previous value.

try this

<?
$value = 235;
$value = printf("%.2f", $value);

echo $value;
?>

Hope it helps.
Cheers

[benbox]

Hi,

I tried that but it didnt seem to work, it just returned nothing...

[Weedpacket]

I tried that but it didnt seem to work

sprintf() instead of printf()

[benbox]

and that will return itself as a var value?
like
$value1 = "3.5621" ;
$value2 = sprintf("%.2f", $value1);

[Weedpacket]

Originally posted by benbox
and that will return itself as a var value?

¿Que?

[maxsslade]

if you want to have the altered value a variable, all you have to do is....

$original_val = "6.5";
$altered_val = number_format($original_val, 2);

if you echo the variable, output will be '6.50'

• Max