header question!

[ErikN]

Hi,
I've made a thumbnail script and it's all working and stuff, but if I want to use it in existing code (with include) it keeps displaying some data instead of the image like this:

ÿØÿàJFIFÿþ ü1L©éÿ^{‡¸zíéלã5ô;j«keqy#|–ö¦PY¶)pŒÑ«žÊXI8’}hÄî¿fŸÙŽ}R->Ãöjø{wݝÁ´ƒàÿÃø’M<»Ãr“ÌžbZÝɸ™PÁãy?fÙ×Äß}

and more of that crap... I think I need to use headers in some sort of way, but I can't figure it out here's my code:

photoalbum.php

<?php
include "nav.php";
include "resize.php";

echo "<br><br>";

if (isset ($id)) {
  $query = "SELECT nick,avater_filename FROM users WHERE id='$id'";
  $exec = mysql_query ($query);
  $result = mysql_fetch_array ($exec);
  $nick = $result["nick"];
  $nick_dir = str_replace (" ","_", $nick);
  $avater_filename = $result["avater_filename"];

  $query = "SELECT filename, comments, date FROM photos WHERE user='$id' ORDER BY filename";
  $exec = mysql_query ($query);

  while ($result = mysql_fetch_array ($exec)) {
    $filename = $result["filename"];

$photo = "photos/$nick_dir/$filename";
create_thumbnail ($photo);
  }
}
?>

resize.php

<?php
function create_thumbnail (&$photo) {
  $photo = imagecreatefromjpeg ("./$photo");
  $photo_dimensions_width = imagesx ($photo);
  $photo_dimensions_height = imagesy ($photo);

  if ($photo_dimensions_width == $photo_dimensions_height) {
    $thumb_dimensions_width = 100;
    $thumb_dimensions_height = 100;
  }

  elseif ($photo_dimensions_width > $photo_dimensions_height) {
    $value = $photo_dimensions_width / 100;
    $thumb_dimensions_width = 100;
    $thumb_dimensions_height = round ($photo_dimensions_height / $value);
  }

  else {
    $value = $photo_dimensions_height / 100;
    $thumb_dimensions_height = 100;
    $thumb_dimensions_width = round ($photo_dimensions_width / $value);
  }

  $thumb = imagecreatetruecolor ($thumb_dimensions_width, $thumb_dimensions_height);
  imagecopyresampled ($thumb, $photo, 0, 0, 0, 0, $thumb_dimensions_width, $thumb_dimensions_height, $photo_dimensions_width, $photo_dimensions_height);
  ImageJpeg($thumb,'',100);
}
?>

[diego25]

You can't combine both into one script because one script sends content type text/html and the other image/jpeg.

Diego

[michael]

Aye.

Write the file and use file_exists and <img> tag to reference it.

You can only send one or the other.

You would get a parse error (output started on X) if you tried to do what you are proposing.

[ErikN]

i've been trying with the img tag but it's not working, can you give an example please?

[yelvington]

This is one of those cases that puzzles me. Why do people forget the basics of HTML when they start coding PHP?

You cannot embed image data in an HTML file.

You must present the image by referring to it from HTML. The browser will fetch the image and assemble the page. PHP does not change those ground rules.

Make one PHP file that creates an HTML page containing an HTML <img src=""> tag. The src URI may refer to a php file, and it may pass urlencoded arguments.

Make another file that finds, resizes, and presents the thumbnail after it emits a proper content-type header:

header('Content-type: image/jpeg');