parameter from URL

[neechee]

Recently, I've install php on Linux and tested it on another pc with windows os. I found that there are some EXTRA error or warning message. for example:
---------- test.php ---------
if($name == none || $name == "")
{
print ("Please select enter your name");
exit;
}

I will get the message like " variable $name not define ... none not define" even though I access this file as url: test.php?name=neechee

What's the setting I need to do to avoid this extra message and let it reconise parameter from url?

[lurius]

You probably have register_globals off...
Try $_GET['name']

-Lurius

[neechee]

so i need to do this?
register_globals on

but ir still giving the same result " undefine variable in line ...."

[lurius]

No you don't have to..

Variables passed in url should be available in $_GET-array.

Like somepage.phtml?param1=3,
in somepage.phtml you could do:

print '<p>Param:' . $_GET['param1'];

If $_GET-array doesn't show up, try $HTTP_GET_VARS-array...
Which version of php are you using?

-Lurius

[neechee]

I'm using php4. I've tested in other web hosting that support php4, I just need to pass parameter thru url like:

test.php?name=neechee

<? print "hello $name:"; ?> // it should print the $name.

why I can't do it as usual? what's the setting I missed out?

[lurius]

So, have you tried
<? print 'hello ' . $_GET['name']; ?>

-Lurius

[neechee]

I've tried <? print 'hello ' . $_GET['name']; ?> and it works if giving url: test.php?name=neechee

if I just accessing test.php without parameter, I get this message
"Notice: Undefined index: name in /var/www/htdocs/test.php on line 1"

which is unusual as I tested in other webhosting with php. It should be able to get paramter from url using neither $_GET-array nor $HTTP_GET_VARS-array in the php code.

Pls help. I believe that's something wrong in my setting.

[lurius]

if I just accessing test.php without parameter, I get this message
"Notice: Undefined index: name in /var/www/htdocs/test.php on line 1"

That's because variable $name hasn't been declared anywhere. PHP gives this warning (notification) if you're using undeclared variable. (Depends on error_level-setting, of course)

"It should be able to get paramter from url using neither $_GET-array nor $HTTP_GET_VARS-array in the php code."

Not if using default (recommended) settings. Check the php-manual, http://www.fi.php.net/manual/en/language.variables.predefined.php for more information.

-Lurius

[neechee]

Lurius, thanks a lot 🙂
I think I might need to roll back to older version If I want to keep the current php codes. Is php4.0 ok for my case?

Anywhere, I feel not convenient for this new feature and easily showing unwanted error message to user when some parameter is missing (designed in purpose for checking). What do you think?

[lurius]

Don't use old versions of php if you really don't have to. New versions have bug-fixes and added functionality and all...

Notifications are good for developing and debugging, but you can turn them off when satisfied with your work...

And this new superglobals-thing is good for not mixing all global data with session-, post- and whatever-data you may have...

-Lurius