Variables, filenames and include()

Major_Tom

My first post - and probably a real newbie question too...

The situation is as follows:
1. I use include() to put together various parts of a HTML page (headers, footings, navigation menu etc.):

index.php:

include(headerstufffile.php)
include(navigation.php)

(some content here)

include(footerstufffile.php)

2. I would like the navigation menu to change depending on which file I'm in. Let's say that in the navigation menu I have a link to a new page, page2.php, with the same includ(navigation.php).

Is there a way to use the name page2.php as a variable in navigation.php to load some different menu items for that page only?

Henks

Not sure if you mean this but it looks like you want a variable variable name which can be done like this:

<?
$var1 = "weekend";
$$var1 = "friday";
?>

The second line assigns the value 'friday' to the variable $weekend so the variable name is variable.

Again, not sure if you mean this and I'm a newbie myself too 🙂

Henk

rIkLuNd

You could do like this in the menu file:

<?php

if($page == "downloads")
{
print "Downloads<br>\n";
print "- Type 1<br>\n";
print "- Type 2<br>\n";
}
else
{
print "Downloads<br>\n";
}
?>

Then you visit the page with the url:
http://www.you.com/index.php?page=downloads

Hope this was what you wanted... 😉

Major_Tom

Originally posted by rIkLuNd

Hope this was what you wanted... 😉 [/B]

I had tried that already actually... But reading your response I decided to retry with a little different approach. It seems the problem is that I had several pages (index.php, page2.php, page3.php etc.) each linking into the navigation.php. I took the content of the various files and saved in separate inc files and include them in index.php according to the 'page=' variable set.

It works! 🙂

Thanks for the replies.

rIkLuNd

You're welcome! :p