Problem with the ISSET function ?

[yaf23]

Could anyone make a suggestion as to what to change to make this test work. Everytime it runs it always is TRUE. Am I using the ISSET function correctly ? if not do you have any suggestions ?

I am trying to test for a URL variable that will be coming in to this page.

The code:

if(isset($GET["table_name"]) == "proj") {
$tab_name = "proj";
echo "TAB NAME : $tab_name";
}
if(isset($GET["table_name"]) == "itsupp") {
$tab_name = "itsupp";
echo "TAB NAME : $tab_name";
}

Thanks,
Yafeu

[AQHost]

Hi Yafeu,

I think what you want is something like this:

if(isset($_GET["table_name"])
{
   if($_GET["table_name"] == "proj")
   { 
      $tab_name = "proj"; 
      echo "TAB NAME : $tab_name"; 
   }
   elseif($_GET["table_name"] == "itsupp")
   { 
      $tab_name = "itsupp"; 
      echo "TAB NAME : $tab_name"; 
   }
   else
   {
      echo "TAB NAME: Was not one of the two named options";
   }
}
else
{
   echo "TAB NAME: Was not set in the URL";
}

Best wishes,
Simon.