String to Int?

TheReverend

Hello,

I've pulled a bunch of numbers from a .txt file with fopen/fread, and I've put them into an array with explode().

However, when I try to compare them, it compares them as strings.

Example:

<?php
// $array[0] == "9"
// $array[1] == "10"

if($array[0] < $array[1])
   echo("Yay!");
else
   echo("No!");

?>

prints: No!

Since it's reading the numbers as a string, it's saying 10 comes before 9. Example: 1, 10, 2, 3, 4, 5, 6, 7, 8, 9

So I'm wondering if there's a way to convert the string to an int (which I don't think is possible) or at least compare these in a natural order--without using natsort()....

leatherback

Hi,

Have you tried settype?:

http://www.phpbuilder.com/manual/function.settype.php

hand

http://www.php3.de/manual/en/function.intval.php

TheReverend

Thanks!

Intval worked like a charm :-)

Settype wasn't quite what I needed, but thanks anyway! :-)!

Dave

[deleted]

I think you haven't noticed your mistake :
== is a comparsion operator, to asign a value to a varianble use =

So this behaves as expected :

<?php
$a = 3;
$b = -2;
print  $a+$b;// returns 1
print  "\n";
print  ($a == $b)?'yes':'no';// returns no
?>

p.s.
To declare type you may also use :

<?php
(int)$a = 3;
(float)$b = -2;
(string)$c = 'mote';
?>

ednark

orange is correct... however be carefull

(int)$val uses $val as an int for only that one time

settype changes the type forever

TheReverend

No, I was just showing what the two arrays equaled. The input is pulled from a text file, not manually like: array[0] = blah blah blah

But thanks! intval works great ;p