remove first characters of string in array.

Haiwatta

I got a array filled with strings.
What I want to do is remove the first three characters (numbers) of every string in the array.

The strings look like this:
010Boten
020Beelden
030Water

And the result should look like this
Boten
Beelden
Water

I think this should be very easy, but I can't find right commando's to get this working.

Arjen.

archangel_617b

There's a million ways of doing this. For string manipulation, I recommend regex in every case. Check [man]ereg_replace/man. To regex your way to freedom, try this:

// below regex explained:
// ^        begining of the line
// [0-9]  characters in that range (numbers)
// +        one or more of these (numbers)
// ()        register, first () pair stored in \1
// .         any character
// *        any number of time (eg the rest of the line) 
$str = ereg_replace('^[0-9]+(.*)', '\1', $str);

Buddha443556

Let's keep it simple.

$rest = substr("abcdef", 3); // returns "def"

Haiwatta

I couldn't get it to work with 'ereg_replace'. Instead I tried 'preg_replace', wich replace text...

I don't get the '^[0-9]+(.*)' part of ereg_replace. Not even after looking in my PHP-handbook or at www.php.net. 😕
Maybe someone could give some explanation?

To get it to work, this is what I did:

for ($i=0;$i<=9;$i++)
{
$search[$i]="'$i'";
}

$replace = "";

$str_x = preg_replace($search, $replace, $str);

so: "010aaa010" becomes "aaa", "020bbb020"becomes "bbb".

But what I want is only the first three numbers to be removed.

Help is appriciated.

Arjen.

Haiwatta

Originally posted by Buddha443556
Let's keep it simple.

$rest = substr("abcdef", 3); // returns "def"

Thanks! That did the job.

This is what I made:

for($i=0;$i<count($str);$i++)
{
$str_x[$i] = substr($str[$i],3);
}

Arjen.