submit buttons as images and php

juschillinnow

This is suppose to submit a bunch of variables to a php script. But it doesn't ....If I change the line to this....

It works fine.

Is there a reason the Image won't work as a proper submit button?

azkworld

I think you're mistaken that it doesn't submit ANY variables.
The image itself won't be submitted, so if you're trying to do
if($submit=="REMOVE"), you won't get it. But you do get other variables.
Alternative (short form, you need to touch up a bit):

<form name=frm>
<input 1>
<input 2>
<input type=hidden name=submit>
<a href="javascript:rem()"><img src="remove.gif"></a>
<a href="javascript:add()"><img src="add.gif"></a>
</form>
<script>
function rem() { frm.submit.value="REMOVE"; frm.submit(); }
function add() { frm.submit.value="ADD"; frm.submit(); }
</script>

swjohnson

for HTML

Weedpacket

Originally posted by juschillinnow
<input type="image" name=submit src="./images/remove.gif" value="REMOVE">

Is there a reason the Image won't work as a proper submit button?

Well, the image submit supplies two pieces of data - the x and y coordinates. If you're checking the form data to see if the submit button was hit, you'll be needing to check to see if those coordinates are set (image inputs were created with server-side image maps in mind).

You Know Where
IMAGE SUBMIT variable names

When submitting a form, it is possible to use an image instead of the standard submit button with a tag like:
<input type="image" src="image.gif" name="sub">
When the user clicks somewhere on the image, the accompanying form will be transmitted to the server with two additional variables, sub_x and sub_y. These contain the coordinates of the user click within the image. The experienced may note that the actual variable names sent by the browser contains a period rather than an underscore, but PHP converts the period to an underscore automatically.

juschillinnow

I think you're mistaken that it doesn't submit ANY variables.
The image itself won't be submitted, so if you're trying to do

askworld I do know that it does submit variable. I just had the wrong wording. But yes! I am trying to do what you had guessed. I am trying to do a:

if($submit == "REMOVE"){}

My Problem is still this:

I can't use or make this a hidden value, because there is also another "submit" button in the same form and they both take the same values except this one is

name=submit value=UPDATE

So is there a way to do this with images like i had orginally mentioned?

herve

Hi,

if you have in your HTML code :

then you test $POST["submit_y"] or $POST["submit_x"]

example :

if ($_POST["submit_x"] > 0)
{
// here the user has clicked on the "submit" image/button

}

Hervé.

juschillinnow

so what you're saying is....

<?
if($POST['submit_X'] >0)
{
do this
}
elseif($POST['submit_y'] >0)
{
do that
}
else
{
?>

<form action = <?$PHP_SELF?> method = post>
<input type=hidden name=something value=Value>
<input type=image name=submit src="./images/image.gif">
<input type=image name=submit src="./images/image2.gif">
</form>
<?}?>

? Would this be correct?

herve

No, you don't need to check both values. One is enough.

$POST["submit_x"] & $POST["submit_y"] are the coordinate
(x,y) in pixels, of the click inside the image. If one of them is <> 0, then it means that the user has click inside the image.

Plus you can't have two differents buttons with the same
name (here "submit")

<?
if ($POST['submit1_X'] >0)
{
// here the user has clicked on the submit1 image/button
}
elseif ($POST['submit2_x'] >0)
{
// here the user has clicked on the submit2 image/button
}
else
{
?>

<form action = <?$PHP_SELF?> method = post>
<input type="hidden" name="something" value="Value">
<input type="image" name="submit1" src="./images/image.gif">
<input type="image" name="submit2" src="./images/image2.gif">
</form>

<?
}
?>

Hervé.

Weedpacket

Originally posted by herve
$POST["submit_x"] & $POST["submit_y"] are the coordinate
(x,y) in pixels, of the click inside the image. If one of them is <> 0, then it means that the user has click inside the image.

Well, not quite; if they happen to click right on the top or left edges of the image (or the top-left corner), then 0s will be returned.

But if that image isn't clicked, those fields won't be set at all, so you just need to test to see if either one isset() or not.

barand

Herve

Plus you can't have two differents buttons with the same name

I've used multiple buttons with same name successfully many times.

For example, to query a employee phone directory table to list all names beginning with A, or B etc.

<input type="submit" name="initial" value="A">
<input type="submit" name="initial" value="B">
. . .
<input type="submit" name="initial" value="Z">

When processing the submitted form

$search = $_POST["initial"] . "%";
SELECT * FROM table WHERE name LIKE '$search'