calling a function from within another function

[martincrumlish]

Hi,

I am working on a bet calculator and have got some help here regarding it before.

I wont go into details of the betting part of the problem just the PHP one.

Basically, I need to call a function from within another function and still return the value to the main PHP script.

function doublecalc($odds1, $odds1a)
{
   if(($status1 == "win") && (($status2 == "void")) 
     {
	//the call to the other function
        $total = singlecalc($odds1, $odds1a, $stake, $rf1, deadheat1, $eachway1, $status1);
	$unitstake = $stake;
	}
	else{
	if(($status1 == "win") && ($status2 == "win")) 
	{
        do the normal function code
        }
return $total;
}

This is a function that will check the values passed and if 2 of the values passed are of a certain value control will go to the other function which will then carry out the calculations (singlecalc)

Any help with this is much appreciated.
Thanks,
Martin

[Weedpacket]

if ($status1=='win' && $status2=='win')
  return [i]insert call to other function here[/i];

Presumably the other function returns its result.

[martincrumlish]

yes, each function returns $total

so, i just put the call to singlecalc after return? Didnt realise it was that simple....

[Weedpacket]

Yep; singlecalc() returns its result to doublecalc() and (as it happens) doublecalc() immediately returns it to wherever it was called from.

[martincrumlish]

thanks

you have saved me a lot of needless coding 🙂