Does $x[y] end with a newline? substr(), or what?

I want to determine if each entry(string) in $array ends with a newline, and if not, add one...so, the following is in a FOR loop:

  

$linecheck=substr($array[$n], -1);
       if (linecheck!="\n") { $array[$n] ="$array[$n]" . "\n";

Not only does this feel like a horrible kludge, it just doesn't work...I've grepped several pages of old posts here, but nothing yet...

any suggestions?

dalecosp

PS I've tried -2 in 'substr'...
I've tried "\015" instead of "\n" in IF

Try substr($array[$n], strlen ($array[$n]) - 1)

Originally posted by Rohan Hill
Try substr($array[$n], strlen ($array[$n]) - 1)

Doesn't look necessary, but I'll try anyway.

$lcheck=substr($array[$n], strlen($array[$n], -1))
              if ($lcheck =="\n") { echo "Hallelujah, it works!"; }

Hmmmmm, still no joy. Thanks anyway....

dalecosp

Any one got a new idea?

This can't be that hard, can it? I'm wondering if I have two different types of newlines, perhaps.............

dalecosp

I know that there is many occurence of line feed :
\n
\r
\015
chr(013)
chr(010)

I'm sure there is some doubles but at least you will not miss one.
Let me know if it works

i'm using a reg exp, very usefull to replace any kind of line feed by a <br> for html display

$chrs = "[\n\r\015".chr(013).chr(010)."]+";  

$string= ereg_replace($chrs, "<br>", $string);

Thanks, I'm going back to work on this one, think we're getting closer to a solution...

Thx for the char list....

dalecosp