date rearanging

[Smifffy]

how would i convert a string like this 20021202153015

into
3:30 - 28/12/2002

[Barak]

$date = date("H:i - d/m/Y", $time);

though I might have the case wrong on the d/m 🙂

[Weedpacket]

Originally posted by Smifffy
how would i convert a string like this 20021202153015

into
3:30 - 28/12/2002

Don't you mean
3:30pm - 02/12/2002?

list($year,$month,$day,$hour,$minute,$second) = sscanf($date, '%4d%2d%2d%2d%2d%2d');
$timestamp = mktime($hour, $minute, $second, $month, $day, $year);
$formatted_date = date("g:ia - d/m/Y",$timestamp);

Alternatively, if you're going to use MySQL-format timestamps out of a MySQL database, you could use MySQL functions to convert them into a more conventional format.

[Barak]

Hmm, I'm too tired - I thought you were converting a unix timestamp hehe. Should have noticed it's about twice the length 🙂