Finding specific occurrence of a character

[The_Chancer]

I am looking to find the second to last occurrence of a character, ie in the following:

/home/~user/websites/~webname~/public_html/folder

I want to be able to get the following:

/home/~user/websites/~webname~/public_html

by trimming the line somehow.

Can strrchr do this ? Or can someone point me in the right direction ?

Thanks,

[J_ystick_FI]

$ADDR = http://pippo.com/index.html

$dir = substr(0,strrchr($ADDR, "/"));

$dir should be http://pippo.com

hope this help..

😃 J@ystick_FI😃

[The_Chancer]

Ah- ha.. I was on the right track with
$dir=substr(strrchr($path,'/'),0,-1);

But I'll try yours out...

Many thanks 😃

[The_Chancer]

Didn't give me the answer I was looking for... gave me '0' instead...

However using this very clunky method (but it'll do until I can work something else out)

$len=strlen(substr(strrchr($path,"/"),1));
$len2=strlen($path);
$dir=substr($path,0,($len2-($len+1)));

Does do the trick... but 3 lines of code for that - surely there is a better way....

[Weedpacket]

preg_match('#^(.*)/[^/]*$#', $string, $match)

matches everything up to but not including the last / and stashes it in $match[1]. If you want to go further back, i.e. n slashes instead of just 1:

preg_match('#^(.*)(?:/[^/]*){[i]n[/i]}$#', $string, $match)

Needless to say, if there aren't any (or enough) slashes, there won't be a match.