Displaying Contents of Directory

[BleedingSky]

Hey guys, I've just finished making a php upload script that actually works, hehe. Only took three different attempts at scripts. Anyway, my next step is being able to display those images within the directory that they are uploaded to. Can anybody help me out here? I want to display all the images that are uploaded onto a html or php page on the net. The images uploaded will be around 450 by 450 and I would also like to resize them when displayed. Thank you in advance for any help that I may receive.

[praxiz]

This is what i use:

$directory = ("../staticpath/" . $dynamicfolder . "/staticpath");
$handle=opendir($directory);
while (false !== ($file = readdir($handle))) {

// this line makes sure you dont list "." or ".."
if ($file != '.' && $file != '..' && $file != 'thumbs' && $file != 'lagtinn') { ?>

<font face="arial" size="-1"><b><? echo "$file"; ?></b></font><br>

<? }} closedir($handle); ?>

Now, ofcourse you can write whatever code you want instead of the font.

<a href="view.php?whichfile=<? echo $file; ?>"><? echo $file; ?></a>

<a href="view.php?whichfile=<? echo $file; ?>"><img src="paths/if/neccessary/<? echo $file; ?>"></a>

See? Just fool around with it, if you get any problems you know where to ask.

Yours Faithfully
Praxiz Consternatio

[BleedingSky]

Thank you very much. I'll give that a try and see if it works.

[BleedingSky]

One quick question, do I change where it says staticpath to the directory I am storing the pics, or does that stay the same? You'll have to excuse my inabilities with this language. I just starting using it last week and I'm more of a graphic artist than a programmer, but I'm trying.

[praxiz]

Ah I just wrote it like that to show you different examples.

If you have a variable that contains the name of a specific folder, you use it like i demonstrated:

$directory = ("../animals/" . $dynamicfolder . "/kittens");

-

so if $directory = "cats";

and you are in
/home/www/images/files/index.php
SIZE=1[/SIZE]
then this will select
/home/www/images/animals/cats/kittens/
and open all images that are there

$directory = ("../animals/dogs");

would just open /home/www/images/dogs/
SIZE=1[/SIZE]

$directory = ("gifs/stuff");

would just open /home/www/images/files/gifs/stuff
SIZE=1[/SIZE]

• Praxiz Consternatio

[BleedingSky]

Ok, thanks.

[BleedingSky]

It's displaying stuff, hehe, but not quite what I want. But, I do think it's on the right track. Right now it's displaying the names of the files that are there, but not the images.

[praxiz]

check out my first reply

<font face="arial" size="-1"><b><? echo "$file"; ?></b></font><br>

this can be anything, including:

<img src="<? echo $file; ?>">

🙂

if you just get broken images then check the source to set the right path so it matches with $directory. 🙂

[BleedingSky]

K, I had the broken images so I tried correcting the path, but I'm afraid I'm still getting the broken images.

The path that the images are in is www.domain.com/public_hmtl/NewDesign/uploader

The path that I've put this new script in is www.domain.com/public_html/NewDesign/

So, the path I've put is:
//a href="view.php?whichfile=<? echo $file; ?>"><img src="/uploader/<? echo $file; ?>"

[BleedingSky]

Just a little update, everything is working perfectly. Now, all I have to do is add some code so that the images are loaded in a default size and everything will be ready to go. Thank you so much for your help.