Increment Day

[netmastan]

hi,

How can I increment Day.??
Let say I get todays day "Fri" by using the following code

$day=date("D");

I want to display nextday(ie,Wed),thurs ....and so on for 31 records.

thanks in advance ..

[diego25]

Maybe something like this? (this is untested)

$now = time();
for ($i=0; $i<31; $i++) {
  $day=date("D", $now);
   print $day;
    $now = $now + 24*60*60;
}

Diego

[Weedpacket]

date("D",strtotime("tomorrow"));

[planetsim]

Um.. this may seem stupid. But whats the point in getting this date increment. Is it just to test or what. I cant think of anything useful for it.

But thats just my opinion

[Weedpacket]

Originally posted by planetsim
Um.. this may seem stupid. But whats the point in getting this date increment. Is it just to test or what. I cant think of anything useful for it.

But thats just my opinion

Here's a way to do it (silly though it is, but it does seem like a strange thing to want):

$all_our_tomorrows = array(
'Friday'=>'Saturday', 'Saturday'=>'Sunday', 'Sunday'=>'Monday',
'Monday'=>'Tuesday', 'Tuesday'=>'Wednesday', 'Wednesday'=>'Thursday',
'Thursday'=>'Friday',
);

$today='Friday';
for($i=0;$i<31;++$i)
{	echo $today.'<br>';
	$today=$all_our_tomorrows[$today];
}

But yes, I do have to question the desire.

[netmastan]

Hi, thanks for the reply.

Actually I got a table with the following fields

Fields are Date,Month,Year,x,y.

so, I can easily display Date,Month,Year,x,y. from the database.

I want to display Day as well but The table does not have this field.

so i am trying to do this way without inserting days into the fields.

$month=date("n");// Display Month as 1..12
$year=date("Y");// Display year as 2002
$day=date("j");// Display day as 1,2..31
$DAY=date("D");//Dislay Day as Mon,

/* I Will select data when todays date,month and year are match with the database.If todays day is Fri,then it /*
/* will increment to next days until the last date of the month */
$res = mysql_query("select Date,Month,Year,x,y from salat where Month='$month' AND Year='$year' AND date='$day'", $dbi);

while(list($Date,$Month,$Year,$x,$y) = mysql_fetch_row($res, $dbi)){

/* Here I want to increment day, ie $day+=1,but $DAY how ? */

echo " $Day | $Date | $Month | $Year |$x | $y<br> ";

}

Let say todays day is friday and there are 31 records

Output should display

Friday |3 |1|2002 |x | y
Sat|4|1|2002|x|y
Mon|5|1|2002|x|Y

.........

[planetsim]

Whats the increment of that date for. Weedpacket gave you one. It should work.

You could try mktime to do it.

[netmastan]

Thank u for the code but

$month=date("n");// Display Month as 1..12
$year=date("Y");// Display year as 2002
$day=date("j");// Display day as 1,2..31
$DAY=date("D"); //Dislay Day as Mon

$all_our_tomorrows = array(
'Fri'=>'Sat', 'Sat'=>'Sun', 'Sun'=>'Mon',
'Mon'=>'Tue', 'Tue'=>'Wed', 'Wed'=>'Thu',
'Thu'=>'Fri',
);//ur code

$today='Wed';//ur code
//Note that I dont' want to declare which day is today.It should use
//$DAY=date("D"); to find out todays day.ie.$today=date("D"); But it's not working
//Day should display starting from today's day.Not from the next day



/* I Will select data when todays date,month and year are match with the database.If todays day is Fri,then it /*
/* will increment to next days until the last date of the month */
$res = mysql_query("select Date,Month,Year,x,y from salat where Month='$month' AND Year='$year' AND date='$day'", $dbi);

while(list($Date,$Month,$Year,$x,$y) = mysql_fetch_row($res, $dbi)){

$today=$all_our_tomorrows[$today];//urcode

echo " $Day | $Date | $Month | $Year |$x | $y<br> ";

}

Any help will be great..

[planetsim]

This isnt tested. Just writing it now..

date("d",mktime(0,0,0,d+1,m,Y));

Now i doubt it will do anything but its kinda what you need to do.

[planetsim]

Weepacket's works good. read up on strototime.

btw i tested mine. It doesnt work..

i tried Weedpacket's and it worked like a charm..

try this

echo date("l dS F, Y",strtotime("last day"));

[Weedpacket]

Originally posted by netmastan
Thank u for the code but

$today='Wed';//ur code
//Note that I dont' want to declare which day is today.It should use
//$DAY=date("D"); to find out todays day.

Then go ahead and use it.

But it's not working
//Day should display starting from today's day.Not from the next day

Then move the increment $today=$all_our_tomorrows[$today] to a position after the spot where $today is to be used. Then it will start from its initial value and then get increased.

I mean, it's not rocket science...

[netmastan]

month=date("n");// Display Month as 1..12
$year=date("Y");// Display year as 2002
$day=date("j");// Display day as 1,2..31
$DAY=date("D"); //Dislay Day as Mon

$all_our_tomorrows = array(
'Fri'=>'Sat', 'Sat'=>'Sun', 'Sun'=>'Mon',
'Mon'=>'Tue', 'Tue'=>'Wed', 'Wed'=>'Thu',
'Thu'=>'Fri',
);//ur code

$today=date("D"); 

$res = mysql_query("select Date,Month,Year,x,y from salat where Month='$month' AND Year='$year' AND date='$day'", $dbi);

while(list($Date,$Month,$Year,$x,$y) = mysql_fetch_row($res, $dbi)){

$today=$all_our_tomorrows[$today];

echo " $today | $Date | $Month | $Year |$x | $y<br> ";

}

sorry.. again.. no luck,everything ok except starting day started at from next day.

I have inserted $today=$all_our_tomorrows[$today]; under while loop. so it will increment till the last record.If i put outside it will display the same day for all the records.

I want to display Day starting from todays Day..

[netmastan]

Any help ???

Thanks in Advance

[Weedpacket]

Originally posted by netmastan

I have inserted $today=$all_our_tomorrows[$today]; under while loop. so it will increment till the last record.If i put outside it will display the same day for all the records.

I want to display Day starting from todays Day..

Did the possibility of doing

echo " $today | $Date | $Month | $Year |$x | $y<br> ";
$today=$all_our_tomorrows[$today];

ever cross your mind? That is what I meant by "after the spot where $today is to be used". I didn't say anything about moving it outside the loop.

[netmastan]

Thanks man.. Actually I did yesterday..it did not work.

Now it's working .

I have also learned something from ur coding ..how to display English day to Arabic day.

$ArbDays = array("Sat"=>"ÇáÓÈÊ",
        "Sun"=>"ÇáÃÍÏ",
        "Mon"=>"ÇáÅËäíä",
        "Tus"=>"ÇáËáÇËÇÁ",
        "Wed"=>"ÇáÃÑÈÚÇÁ",
        "Thu"=>"ÇáÎãíÓ",
        "Fri"=>"ÇáÌãÚÉ");

thanks a lot .. NOw i need to know how to convert Georgian Date to Islamic Date ..