Prefixing Files with PHP

rheroux

Alright, here's the scenario. I have a bunch of .txt files that have numbers in them ranging from 0 to 500 or so. What I want to do is prefix the letter j infront of the number if it's two digits or more.

So for instance, when PHP process the file, and it sees the number 3 it won't put j in front of it, but if it sees the number 10 it will or if it sees the number 493 it will.

Is there anyway to do this? I'm sure it's a regexp function that I have to use, but admittedly, I suck at coming up with regexp strings.

Any help is appreciated.

diego25

Maybe something like this?

$number = "10";

if (strlen($number) >= 2) {
$number = 'j' + $number;
}

Diego

rheroux

I think I would have to concatenate the j rather than adding it.

Something like this may work:

$path = "c:\somefile.txt"
$fp = fopen($path);
$contents = fread($fp, filesize);
rewind($fp);

if(ereg("<regexphere>",$contents))
{
$contents = "j" . $string;
$blah = fwrite($fp,$contents)
}

The code may not be perfect, but that's the basic premise.

I'm just not sure on how to setup the regexp to look for only number with two digits or more.

diego25

Oops, yeah, I meant to concatenate, not add...I've been working with Java lately 🙂

Anyway, this works for me:

<?

$variable = "1
10
2
20
3
300
50
300";

print preg_replace('/(\d{2,})/', "j$1", $variable);
?>

Diego

rheroux

I tried implementing that code...all it does is echo the variable. The code I need needs to be somewhat dynamic since there could be 20 numbers with 2 digits or more, or there might be 190, it all depends.

Plus, the variable isn't predefined since I'm pulling it from a file. Any regexp gurus out there?

kevinsequeira

how do get the list of files ? do u run through a directory or is it from a database. The reason i ask is how do finally get the file name, is like filename.txt or c://directory/filename.txt ???

rheroux

It runs through a directory like so:

$dir = "somedir";
$blah = opendir($dir);
while (false !== ($file = readdir($blah)))
{
if($file == "." || $file == "..")
{
}
else
{
$path = $dir . "/" . $file;
$fp = fopen($path, "r+");
$contents = fread($fp,filesize($path));
if(ereg("regexp",$contents))
{
rewind($fp);
$string = "j" . $contents;
$write = fwrite($fp,$string);
}
}

I think I have all the code down except the regexp part.

kevinsequeira

could u paste the content of a sample text file ?? You need to add j to the contents right, not to the file text name, like 100.txt => j100.txt !!!

diego25

Yeah, my regexp does replace 10, or a 100 numbers with more than 2 digits. That's why my $variable is multiline and with numbers with many digits. If you ran the program you'd know that it produces the output you want...

I haven't tested it, but this should probably work:

$fp = fopen($path, "r");
$contents = fread($fp,filesize($path));
fclose($fp);
$contents = preg_replace('/(d{2,})/', "j$1", $contents);
$fp = fopen($path, 'w');
$write = fwrite($fp,$string, strlen($string));

Diego

rheroux

@kevinsequeria:

No, no. I need it to read the file first, and within the file itself are numbers ranging from 0 to 999. If the number is 2 digits or more, then I need to prepend a j beside it.

For instance, say the text file looks like this:

APPEND amtgen01
IF THEN BEGIN 449
SAY @0
IF THEN EXTERN ~BKACHI~ 46
END

IF THEN BEGIN 450
SAY @1
IF THEN EXTERN ~BKACHI~ 47
END

IF THEN BEGIN j451
SAY @2
IF THEN EXTERN ~BKACHI~ 48
END
END

I need PHP to go through it and make it look like this:

APPEND amtgen01
IF THEN BEGIN j449
SAY @0
IF THEN EXTERN ~BKACHI~ j46
END

IF THEN BEGIN j450
SAY @1
IF THEN EXTERN ~BKACHI~ j47
END

IF THEN BEGIN j451
SAY @2
IF THEN EXTERN ~BKACHI~ j48
END
END

@: I'll try that now.

rheroux

Sorry to bring this up again, but I still can't get this working the way I want it to.

Here's some code:

$dir = "somedir"; 
$blah = opendir($dir); 
while (false !== ($file = readdir($blah))) 
{ 
if($file == "." || $file == "..") 
{ 
} 
else 
{ 
$path = $dir . "/" . $file; 
$fp = fopen($path, "r+"); 
$contents = fread($fp,filesize($path)); 
if(ereg("THEN BEGIN [0-9]",$contents)) 
{ 
rewind($fp); 
$string = substr_replace($contents,'j',-1,0) 
$write = fwrite($fp,$string,strlen($string)); 
} 
}

From my rudimentary understanding of regexp, this should search for THEN BEGIN 0 -> THEN BEGIN 9 and then substr_replace counts back 1 place from the right side of the string and inserts a j in there.

However, this of course isn't working. Any thoughts? I've read that preg_match is a better option than regexp in quite a few places. But I haven't the foggiest on how to create preg expressions.

Any help is, as always, appreciated.

diego25

Are you trying to do the same thing as before? 'cause I thought you wanted to add the j on the left side, not the right side.

Diego

rheroux

Yeah, I still want to do the same thing as before.

My understanding of substr_replace() was that if you specified a negative number, it will count from the right side of the string instead of the left side.

So, where this string is concerned for instance:

$contents = 'THEN BEGIN 1';

$contents = substr_replace($contents,'j',-1,0);

So, after that script was run, $contents would equal 'THEN BEGIN j1'.

Or am I understanding substr_replace wrong?

diego25

I don't know what your problem is, 'cause

<?php

$contents = 'THEN BEGIN 1';

$contents = substr_replace($contents,'j',-1,0);
print $contents;

?>

runs fine...It inserts the 'j' besides the 1.

Diego