Need help with some code

[waterboy]

This is the error i get

Image :Array
Warning: filesize() [function.filesize]: Stat failed for (errno=2 - No such file or directory) in /var/apache/htdocs/modules/divebase/preview.php on line 33
Filesize :
Warning: fopen() expects parameter 1 to be string, array given in /var/apache/htdocs/modules/divebase/preview.php on line 40

Warning: filesize() [function.filesize]: Stat failed for Array (errno=2 - No such file or directory) in /var/apache/htdocs/modules/divebase/preview.php on line 40

Warning: fread(): supplied argument is not a valid stream resource in /var/apache/htdocs/modules/divebase/preview.php on line 40

And this is the code

if ($image == 'none') {
echo "<center><table width=75%><tr><td><img src=images/divebase/no.gif width=250></td>";
} else {
echo "Image :",$image;
$filesize2 = filesize($image);
echo "Filesize : ",$filesize2;
$file_size2 = round($filesize2 / 1024 * 100) / 100 . "";
if ($file_size2 > "2000.0") {
print "<center>Image is too large</center>";
die;
}
$data = addslashes(fread(fopen($image, "r"), filesize($image)));
$result = mysql_query("INSERT INTO divebase_img values('','$data','$image','$filesize')");

                            if (!result) {
                                                            echo "Failed to Connect";
                            } else {
                                                            $id = mysql_insert_id();
                                                            echo "<center><table><tr><td><img src=modules/divebase/show.php?id=$id></td>";
                            }

}

[cgraz]

Well first of all, your commas should be periods to conctenate.

echo "Image :",$image; 

should be

echo "Image : " . $image . "";

and

echo "Filesize : ",$filesize2;

should be

echo "Filesize : " . $filesize2 . "";

and I think

$file_size2 = round($filesize2 / 1024 * 100) / 100 . ""; 

should be something like

$file_size2 = round(($filesize2 / 1024 * 100) / 100) . ""; 

$result = mysql_query("INSERT INTO divebase_img values('','$data','$image','$filesize')"); 

should be

$result = mysql_query("INSERT INTO divebase_img (field1, date, image, filesize) VALUES('','$data','$image','$filesize')"); 

// adjust field1, date, image, and filesize to whatever your field names are

and

if (!result) { 

should be

if (!$result) { 
// don't forget the dollar sign to check for variable result

Cgraz

[Weedpacket]

Originally posted by cgraz
Well first of all, your commas should be periods to conctenate.

echo "Image :",$image; 

[/B]

Nothing wrong with that. The last point is valid, though, and the second-to-last is a good idea. The third-to-last may or may not be correct depending on what is wanted.

The errors are basically saying that the given value of $image is bad - "no such file or directory", as the error from line 33 says. The rest are knock-on consequences of that. In fact, as the code you've written says, $image is an array - not a string. Not knowing anything about where $image is supposd to be coming from or what it's supposed to be (I can guess, but it's been yonks since I've worked with register_globals turned on) I can't say any more than that.

[waterboy]

The variable Image come from here

					echo "<td width=\"10%\"><p align=right>Image:</td><td width=\"80%\"><p align=\"left\"> 

<input type=file name=image> </td></tr><tr>" . "<td width=\"10%\">

<p align=right>History:</td><td width=\"80%\"><p align=\"left\"><textarea name=history cols=\"50\" rows=\"5\" value=N/A></textarea></td></tr><tr>" . "<td width=\"10%\"><p align=right>Location:</td><td width=\"80%\"><p align=\"left\"><textarea name=location cols=\"50\" rows=\"5\" value=N/A></textarea></td></tr><tr>" . "<td width=\"10%\"><p align=right>Technical:</td><td width=\"80%\"><p align=\"left\"><textarea name=technical cols=\"50\" rows=\"5\" value=N/A></textarea></td></tr><tr>" . "<td width=\"10%\"><p align=right>Features:</td><td width=\"80%\"><p align=\"left\"><textarea name=features cols=\"50\" rows=\"5\" value=N/A></textarea></td></tr><tr>";

Happy new year to one and All

[Weedpacket]

(You do realise you don't need to write all your HTML in PHP echo statements, don't you?)

Have a look in the manual in the section on Uploading Files. I wouldn't have anything to say that's not already there.

[waterboy]

Can simeone give me a hint how to solved . My probleme ?
I tryed all the sujestion but still cant get it to work.

I dont understand that when i do an echo $image it prints array.
So how can i get the path that should be in that array and print it??

Any one willing to help me on this project is welcome!

http://divesitenet.com:8080/modules.php?name=divebase

Thanks!